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Gnesinka [82]
3 years ago
7

Your Body PartsLabel all these parts of your body.​

Chemistry
1 answer:
Alecsey [184]3 years ago
7 0

Answer: hope this helps:)

Explanation:

Neck

Ear

Shoulder

Thigh

Forehead

Wrist

Arm

Chest

Foot

Hand

Forearm

Cheek

Ankle

Face

Nostril

Abdomen

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CuSO4.5H2O(k) ısı CuSO4(k) + 5 H2O(g) eşitliğine göre bakır sülfatın kristal suyu miktarı ve kaba formülü hesaplanacaktır.
baherus [9]

Answer:

159.609 g/mol

Explanation:

According to the CuSO4.5H2O (k) heat CuSO4 (k) + 5 H2O (g) equation, the crystal water amount of copper sulfate and its rough formula will be calculated.

Weight of copper sulfate containing crystal water = m1 = 249.62… g

Weight of copper sulfate without crystal water weighed = m2 = 159.62 g

Accordingly, calculate the x and y values ​​in the molecular formula of copper sulfate (xCuSO4.yH2O).

3 0
2 years ago
Which direction does thermal energy flow in the following diagram? the picture is of someone holding an ice cream cone
Sliva [168]
The answer is B. Heat flows from the hand to the ice cream. The state of equilibrium won't occur for this since the only reactant is heat.
8 0
3 years ago
Read 2 more answers
The elements least likely to form bonds are found in which group? 15, 16, 17, 18
Ipatiy [6.2K]

Answer:

D.18

Explanation:

Edgenuity

3 0
2 years ago
Read 2 more answers
The pH of a solution is measured as 4.5. What is the hydrogen ion concentration of the solution?
Bond [772]

Answer:

[H⁺] =  3.16 × 10⁻⁵ mol/L

Explanation:

Given data:

pH of solution = 4.5

Hydrogen ion concentration = ?

Solution;

pH = -log [H⁺]

we will rearrange this formula:

[H⁺] =  10∧-pH

[H⁺] = 10⁻⁴°⁵

[H⁺] =  3.16 × 10⁻⁵ mol/L

4 0
2 years ago
You are given a solution that is 518 mM lactose. You need to make up 4.5 L of 16.7 mM solution. What volume do you need to trans
OLga [1]

Answer:

The volume you need to transfer from the stock solution is 0.145 l

Explanation:

Since the number of moles of lactose in the volume of stock solution that you transfer will be the same as the number of moles of lactose in the final solution, you can use this expression:

number of moles in volume to transfer = number of moles in the final solution

Since number of moles = concentration * volume (if the concentration is expressed in molarity), then:

Ci * Vi = Cf * Vf

where:

Ci = concentration of the stock solution.

Vi = volume of the stock solution to be transferred.

Cf = concentration of the final solution

Vf = volume of the final solution

Then, replacing with the data:

518 mM * Vi = 16.7 mM * 4.5 l

Vi = 16.7 mM * 4.5 l / 518 mM

<u>Vi = 0.145 l or 145 ml</u>

Notice that any concentration unit can be used, as long as the units of the concentration of the stock and final solution are the same.

4 0
3 years ago
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