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Gnesinka [82]
3 years ago
7

Your Body PartsLabel all these parts of your body.​

Chemistry
1 answer:
Alecsey [184]3 years ago
7 0

Answer: hope this helps:)

Explanation:

Neck

Ear

Shoulder

Thigh

Forehead

Wrist

Arm

Chest

Foot

Hand

Forearm

Cheek

Ankle

Face

Nostril

Abdomen

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The pH of a solution is 2.0. Which statement is correct?
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The relationship of pH and concentration of H+ ion is pH = -lg[H+]. So the concentration of H+ is 10^(-2). And [OH-][H+]=10^(-14). pOH + pH = 14. So the right answer is A.

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Maria poured 25 grams of water into a beaker. She stirred in 5 grams of salt. The salt dissolved. What is the total mass of Mari
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The answer to your question is: 30 g

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Jonathan raised 60 goats, then entered into a series of business transactions. He traded all the goats for sheep at an exchange
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A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

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Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
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