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2 years ago

Your Body PartsLabel all these parts of your body.

Chemistry

1 answer:

Alecsey [184]2 years ago

7 0

Answer: hope this helps:)

Explanation:

Neck

Ear

Shoulder

Thigh

Forehead

Wrist

Arm

Chest

Foot

Hand

Forearm

Cheek

Ankle

Face

Nostril

Abdomen

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How are Celsius, Kelvin, and Fahrenheit scales similar? How are they different? Considering their differences, think of one scen

PIT_PIT [208]

Answer:

they are similar becauze they measure temperature

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3 years ago

JOSE BOUGHT 750 BAGS OF PEANUTS FOR 375 HE INTENDS TO SELL EACH BAG FOR 0.15 MORE THAN HE PAID HOW MUCH SHOULD HE CHARGE FOR EAC

labwork [276]

He paid 2 dollars for each bag. Then add 15 cents for that and he would charge $2.15 for each bag.

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3 years ago

Read 2 more answers

Please help me out with this

d1i1m1o1n [39]

Answer
I think it’s 5
Explanation

4 0

2 years ago

How many moles of water were lost if the amount of water lost was 0.456 grams? Do not include units and assume three significant

nika2105 [10]

<h3>Answer:</h3>

0.0253 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.456 g H₂O (water)

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of H - 1.01 g/mol

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 0.456 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 0.025305 \ mol \ H_2O$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.025305 mol H₂O ≈ 0.0253 mol H₂O

3 0

2 years ago

A chemist needs to make 250 mL of a 2.50 M aqueous solution of ammonium hydroxide from a 6.00 M ammonium hydroxide solution. How

Furkat [3]

Answer:

250 mL (total solution) = 104 mL (stock solution) + 146 mL (water)

Explanation:

Data Given

M1 = 6.00 M

M2 = 2.5 M

V1 = 250 mL

V2 = ?

Solution:

As the chemist needs to prepare 250 mL of solution from 6.00 M ammonium hydroxide solution to prepare a 2.50 M aqueous solution of ammonium hydroxide.

Now

first he have to determine the amount of ammonium hydroxide solution that will be taken from6.00 M ammonium hydroxide solution

For this Purpose we use the following formula

M1V1=M2V2

Put values from given data in the formula

6 x V1 = 2.5 x 250

Rearrange the equation

V1 = 2.5 x 250 /6

V1 = 104 mL

So 104 mL is the volume of the solution which we have to take from the 6.00 M ammonium hydroxide solution to prepare 2.5 M aqueous solution of ammonium hydroxide

But we have to prepare 250 mL of the solution.

so the chemist will take 104 mL from 6.00 M ammonium hydroxide solution and have to add 146 mL water to make 250 mL of new solution.

in this question you have to tell about the amount of water that is 146 mL

250 mL (total solution) = 104 mL (stock solution) + 146 mL (water)

7 0

2 years ago

Your Body PartsLabel all these parts of your body.​

Your Body PartsLabel all these parts of your body.