Answer:
1.)calcium+hydrochloric acid -->calcium chloride +hydrogen
2.)Ca + 2HCl -->CaCl2 + H2
3.)3.55g
Explanation:
1.) pretty self explanatory
2.)Ca + HCl -->CaCl2 + H2
then balance
Ca + 2HCl -->CaCl2 + H2 (+2 infront of Hcl)
3.) take calcium and calcium chloride
Ca + CaCl2
then you need the relative atomic mass of both
Ca=40
CaCl2=71 (40+(35.5x2))
Ca=40 40/40=1 1x2=2g
Then repeat that exact equation for calcium chloride
CaCl2=71 71/40=1.775 1.775x3=3.55g
Freezing point depression depends of the number of particles of the solute in the solution.
1)Pure water have highest freezing point. All other solutions with given solutes will have lower temperatures.
2) The more particles of the solute in the solution the lower freezing point is going to be.
<span>b. 1.0 m NaCl ( dissociates and give 2 mol ions (1 mol Na⁺ and 1 mol Cl⁻))
c. 1.0 m K3PO4 (</span>dissociates and give 4 mol ions (3 mol K⁺ and 1 mol PO4³⁻)<span>
d. 1.0 m CaCl2 (</span>dissociates and give 3 mol ions (1 mol Ca²⁺ and 2 mol Cl⁻))<span>
e. 1.0 m glucose (c6h12o6) (glucose does not dissociate, and solution have
1 mole of particles of the solute(glucose))
The largest number of particles has </span>1.0 m K3PO4 solution, and it is has lowest freezing point . Answer is C.
Hey there!
D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL
The relative molecular mass of the gas : 64 g/mol
<h3>Further explanation</h3>
Given
Helium rate = 4x an unknown gas
Required
The relative molecular mass of the gas
Solution
Graham's Law
r₁=4 x r₂
r₁ = Helium rate
r₂ = unknown gas rate
M₁= relative molecular mass of Helium = 4 g/mol
M₂ = relative molecular mass of the gas
Input the value :
