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3 years ago

Fill in the blanks with appropriate options given in below:

Chemistry

1 answer:

jarptica [38.1K]3 years ago

4 0

Answer:

1) -COOH

2) -NH2

3) hydrogen bonds

4) dispersion forces

5) -CH3

6) hydrogen bonds

7) negative

8) negative

9) positive

Explanation:

Alanine has a -COOH and a -NH2 group available to form hydrogen bonds with water molecules.

Although there are some potential dispersion forces between the terminal -CH3 group of alanine and hexane molecules, we expect the hydrogen bonds between alanine and water to be stronger.

Stronger intermolecular attractive forces between alanine and water lead to a more negative ΔHmix and more negative (smaller positive) ΔHsoln for water than for hexane.

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PLEASE I REALLY NEED ANSWER REAL QUICK

DENIUS [597]

Answer:

b. 760 g

Explanation:

The mass of the solution = 800 g

5% of NaCl by mass of the solution can be determined as follows;

5% of 800 = $\frac{5}{100}$ × 800

= 5 × 8

= 40 g

The mass of NaCl in the solution is 40 g.

The mass of water = mass of solution - mass of NaCl

= 800 - 40

= 760 g

Therefore, the mass of water required is 760 g.

5 0

3 years ago

Determine the partial pressure and number of moles of each gas in a 15.75-L vessel at 30.0 C containing a mixture of xenon and n

lawyer [7]

Answer:

The Partial pressure of Xe and Ne will be 4.95 atm and 1.55 atm. The number of moles of Xe and Ne will be 3.13 and 0.981

Explanation:

Let the total pressure of the vessel= 6.5 atm and mole fraction of Xenon= 0.761

As we know,

$\chi_{Ne} + \chi_{Xe} = 1\\\chi_{Ne}= 1- 0.761\\\chi_{Ne}= 0.239$

According to Dalton's Law of partial pressure-

$P_i=\chi_i\times P_{total}$

Where,

$P_i=$ The pressure of the gas component in the mixture

$\chi_i=$ Mole fraction of that gas component

$P_t=$ The total pressure of the mixture

$P_{Xe}=(0.761)\times(6.5)\\P_{Xe}= 4.95 atm\\\\\\P_{Ne}=(0.239)\imes (6.5)\\P_{Ne}= 1.55 atm$

Calculation:

To calculate the number of moles,

PV=nRT

$n=\frac{PV}{RT}$

$n_{Xe}= \frac{4.95\times 15.75}{0.0821\times303 }\\ n_{Xe}= \frac{77.96}{24.87} \\n_{Xe}= 3.13\,mole \\\\\\n_{Ne}= \frac{1.55\times 15.75}{0.0821\times303 }\\\\n_{Ne}=\frac{24.41}{24.87}\\ n_{Ne}=0.981 \,mole$

Learn more about Dalton's Law of partial pressure here;

brainly.com/question/14119417

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4 0

2 years ago

In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c

Darya [45]

Answer:

0.382g

Explanation:

Step 1: Write the reduction half-reaction

Al³⁺(aq) + 3 e⁻ ⇒ Al(s)

Step 2: Calculate the mass of Al produced when a current of 100. A passes through the cell for 41.0 s

We will use the following relationships.

1 A = 1 C/s

1 mole of electrons has a charge of 96486 C (Faraday's constant)

1 mole of Al is produced when 3 moles of electrons pass through the cell.

The molar mass of Al is 26.98 g/mol.

The mass of Al produced is:

$41.0s \times \frac{100C}{s} \times \frac{1mole^{-} }{96486C} \times \frac{1molAl}{3mole^{-} } \times \frac{26.98gAl}{1molAl} = 0.382gAl$

7 0

3 years ago

Watch the following videos on molecule mixing encapsulators:

qwelly [4]

Answer:

here you go

Explanation:

6 0

2 years ago

What is a compounds

V125BC [204]

a compound in chemistry, is any substance that is formed when two or more chemical elements are chemically bonded together. A prime example of this is H20. You are combining hydrogen to oxygen, giving you a compund element. I hope this helps you. :)

3 0

3 years ago