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stepladder [879]
3 years ago
15

Why are the temperatures on other objects in the solar system more extreme than the temperatures on the Earth?

Chemistry
1 answer:
musickatia [10]3 years ago
7 0
Hello there!

It is just based on the fact that they are closer or further away from the Sun.

Hope This Helps You!
Good Luck :) 
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Calculate the ph of a 0.10 m solution of hypochlorous acid, hocl. ka of hocl is 3.5×10−8 at 25 ∘c. express your answer numerical
Viktor [21]

Answer:

4.23.

Explanation:

<em>∵ pH = - log[H⁺].</em>

<em>For weak acids:</em>

∵ [H⁺] = √(ka)(c).

∴ [H⁺] = √(3.5 × 10⁻⁸)(0.10 M) = 5.92 x 10⁻⁵.

∴ pH = - log[H⁺] = - log(5.92 x 10⁻⁵) = 4.2279 ≅ 4.23.

3 0
3 years ago
Please help with this science assignment
mars1129 [50]

both of the answers are bone

Explanation:

Mark me as brainliest

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3 years ago
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How many valence electrons can atoms of non metals have?
Dmitry_Shevchenko [17]

1 to 8 valence electrons

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What dose buoyancy have to do with jumping?
Naddika [18.5K]
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The buoyancy offsets the force of gravity that would otherwise cause the object to sink (if the body's density is greater than the density of the fluid in which it is immersed) or rise (if it's less). An object that has neutral buoyancy will neither sink nor rise. 

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8 0
3 years ago
0.60 atm of SO3 and 0.30 atm of SO2are placed in a container and the system is allowed to reach equilibrium. Calculate the press
frozen [14]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The pressure is [O_2] =  4.8 *10^{-5} \ atm

Explanation:

From the question we are told that

     The  pressure of  SO_3 is  [SO_3 ] =  0.63 \ atm

     The  pressure of  SO_2 is  [SO_ 2]  =  0.30 \ atm

      The equilibrium constant is K_p  =  1.2 *10^{-5}

     The  reaction is

           2SO_3 _{(g)} ⇔ 2SO_2_{(g)} +  O_2 _{(g)}

Generally the equilibrium constant is mathematically represented as

           K_p  =  \frac{(SO_2)^2 *  (O_2)}{(SO_3)^2}

=>         [O_2] =  \frac{k_p * [SO_3] ^2 }{[SO_2]^2}

substituting values

            [O_2] =  \frac{1.2 *10^{-5} * 0.60 ^2 }{0.30^2}

             [O_2] =  4.8 *10^{-5} \ atm

     

8 0
3 years ago
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