Answer:
26.6 m/s
Explanation:
Given:
Δy = 2.1 m
t = 5.35 s
a = -9.8 m/s²
Find: v₀
Δy = v₀ t + ½ at²
(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²
v₀ = 26.6 m/s
Neutrons have a zero charge but consist of mass.
Answer:
0.72 kg per cubic m
Explanation:
Mass = 14.4 kg
Volume = lbh = 4*1*5 = 20 cubic m
<h2>
The average speed of the moon around the earth is 1021.74 m/s</h2>
Explanation:
Radius of moon around earth, r = 3.84 × 10⁸ m
Circumference of orbit = 2πr = 2 x 3.14 x 3.84 × 10⁸
Circumference of orbit = 2.41 x 10⁹ m
Time taken, t = 27.3 days = 27.3 x 24 x 60 x 60 = 2358720 seconds
We have
Circumference of orbit = Speed of moon x Time taken
2.41 x 10⁹ = Speed of moon x 2358720
Speed of moon = 1021.74 m/s
The average speed of the moon around the earth is 1021.74 m/s
We can assume the process to be adiabatic such that we can make use of the formula:
W = R (T2 - T1) / (γ - 1)
W = 8.314 (297 - 17) / (1.4 - 1)
W = 700 J/mole
multiplying the number of moles
W = 700 (0.43)
W = 301 J
The work done is 301 J.
