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kogti [31]
3 years ago
10

A major component of gasoline is octane (C8H18). When liquid octane is burned in air it reacts with oxygen gas to produce carbon

dioxide gas and water vapor.
Calculate the moles of water produced by the reaction of 1.00 mol of oxygen. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant figures.
Chemistry
1 answer:
Paraphin [41]3 years ago
7 0

Answer:

The answer to your question is 0.4 moles of Oxygen

Explanation:

Data

Octane (C₈H₈)

Oxygen (O₂)

Carbon dioxide (CO₂)

Water (H₂O)

moles of water = ?

moles of Oxygen = 1

Balanced chemical reaction

                   C₈H₈  +10O₂  ⇒   8CO₂  +  4H₂O

              Reactant     Element     Products

                    8                 C                 8

                    8                 H                 8  

                   20                O               20  

Use proportions to solve this problem

                  10 moles of Oxygen ----------------- 4 moles of water

                    1 mol of Oxygen     ------------------ x

                    x = (4 x 1) / 10

                    x = 4 / 10

                    x = 0.4 moles of water

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Explanation:

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130 gCl2 x \frac{1 mol Cl2 }{70.90 gCl2} = 1.83 mol Cl2

Then we need to convert 1.83 mol de Cl2 to moles of Cl. We have 2 moles of Cl in every Cl2 molecule so we just need to multiply by 2.

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