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Marat540 [252]
3 years ago
5

3. You measure a cube and determine that its sides are 0.65m. You place the cube on a mass scale and determine that this cube ha

s a mass of 10,500 grams. What is the density of this cube in units of kg/m3 and in units of g/mL?
Chemistry
1 answer:
amid [387]3 years ago
7 0

The density of the cube in-

Kg/m³= 38.234 kg/m³

g/mL= 0.038234 g/mL

Explanation:

We know that volume of the cube equals m ³

Where “m” equals side of the cube

Given data-

Side of the cube=0.65m

mass of the cube= 10,500 gm

We know that 1000gm= 1 kg

Hence, 10,500 gm= 10.5 kg

Volume of the cube= (0.65)³

∴ Volume= 0.274625 m ³

We know that density = mass/volume

⇒Substituting the value of mass and volume, we get-

⇒Density= 10.5/0.274625= 38.234 kg/m³

We know that 1 kg/m³= 0.001 g/mL

Hence 38.234 kg/m³ would equal 0.038234 g/mL

Hence the density of the cube is 38.234 kg/m³ and 0.038234 g/mL

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Which ion is responsible for basic properties?
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Answer:

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Iron (Fe) has three isotopes. Calculate the average atomic mass of the element Fe using the following data: Isotope atomic mass
Maksim231197 [3]

Answer:

Average atomic mass = 55.83 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})+(\frac {\%\ of\ the\ third\ isotope}{100}\times {Mass\ of\ the\ third\ isotope})

Given that:

For first isotope, Fe-54:

% = 6 %

Mass = 53.94 amu

For second isotope, Fe-56:

% = 92 %

Mass = 55.93 amu

For third isotope, Fe-57:

% = 2 %

Mass = 56.94 amu

Thus,  

Average\ atomic\ mass=\frac{6}{100}\times {53.94}+\frac{92}{100}\times {55.93}+\frac{2}{100}\times {56.94}

<u>Average atomic mass = 55.83 amu</u>

5 0
3 years ago
Consider the following reaction. SO2Cl2 → SO2 + Cl2. After collecting experimental data you found that plotting ln[SO2Cl2] vs. t
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Answer:

[SO_2Cl_2]_{600}= 0.0842 M

Explanation:

Some theoretical knowledge is required here. We should understand that whenever we plot the natural logarithm, ln, of a concentration vs. time and obtain a straight line, this indicates a first-order reaction. That said, since this is the case here, we have a first-order reaction with respect to SO_2Cl_2.

The linear equation has the following terms:

y = -0.000290t - 2.30

It is a linear form of the integrated first-order law equation:

ln[SO_2Cl_2]_t = -kt + ln[SO_2Cl_2]_o

Therefore, the rate constant, k, is:

k = 0.000290 s^{-1}

The natural logarithm of initial molarity is:

ln[SO_2Cl_2]_o = -2.30

Using the equation, we may substitute for t = 600 s and obtain the natural logarithm of the concentration at that time:

ln[SO_2Cl_2]_{600} = -0.000290 s^{-1}\cdot 600 s - 2.30 = -2.474

Take the antilog of both sides to find the actual molarity:

[SO_2Cl_2]_{600}=e^{-2.474} = 0.0842 M

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Pani-rosa [81]
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Hope this works,
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5 0
3 years ago
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