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3 years ago

8

A sample of hydrogen gas is placed in a 0.500 L container at 295K. The gas pressure is 1.442 bar. How many moles of H2 gas are i

n the container.

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

0.0294

Explanation:

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A dunk tank hold 30,533 moles of water? How many grams of water are in the tank?

liubo4ka [24]

The mass of water in the tank, given the data from the question is 549594 g

<h3> Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mass of water in the tank</h3>

From the question given above, the following data were obtained:

Mole of water = 30533 moles
Molar mass of water = 18 g/mol
Mass of water = ?

The mass of the water can be obtained as follow:

Mass = mole × molar mass

Mass of water = 30533 × 18

Mass of water = 549594 g

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1 year ago

Explain how two object create heat went rub quickly

sergiy2304 [10]

Answer:

friction

Explanation:

the resistance that one surface or object encounters when moving over another.

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2 years ago

1. Energy changes occur as *

alexandr1967 [171]

Number 3 i think is <span>d.heat moves from an object of higher temperature to an object of lower temperature</span>

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3 years ago

How many grams of hydrochloric acid are in 0.500 L of solution

neonofarm [45]

Answer:

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3 years ago

A gas that was heated to 150 Celsius has a new volume of 1587.4 L. What was its volume when its temperature was 100 Celsius?

sdas [7]

Answer:

$\boxed {\boxed {\sf 1058.3 \ L}}$

Explanation:

We are asked to find the new volume of a gas after a change in temperature. We will use Charles's Law, which states the volume of a gas is directly proportional to the temperature. The formula for this law is:

$\frac {V_1}{T_1}= \frac{V_2}{T_2}$

The gas was heated to 150 degrees Celsius and had a volume of 1587.4 liters.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{T_2}$

The temperature was 100 degrees Celsius, but the volume is unknown.

$\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C}$

We are solving for the volume at 100 degrees Celsius, so we must isolate the variable V₂. It is being divided by 100°C and the inverse of division is multiplication. Multiply both sides of the equation by 100°C.

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = \frac {V_2}{100 \textdegree C} * 100 \textdegree C$

$100 \textdegree C *\frac {1587.4 \ L }{150 \textdegree C} = V_2$

The units of degrees Celsius cancel.

$100 *\frac {1587.4 \ L }{150 } = V_2$

$100 *10.58266667 \ L = V_2$

$1058.266667 \ L = V_2$

The original measurement of volume has 5 significant figures, so our answer must have the same. For the number we calculated, that is the tenth place. The 6 in the hundredth place to the right tells us to round to 2 up to a 3.

$1058.3 \ L = V_2$

The volume of the gas at 100 degrees Celsius is approximately <u>1058.3 liters.</u>

6 0

3 years ago