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3 years ago

8

A sample of hydrogen gas is placed in a 0.500 L container at 295K. The gas pressure is 1.442 bar. How many moles of H2 gas are i

n the container.

1 answer:

steposvetlana [31]3 years ago

5 0

Answer:

0.0294

Explanation:

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The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 8.600 g C6H6 is burned and the heat pr

jenyasd209 [6]

Answer : The final temperature of the water is, $22.5166^oC$

Explanation : Given,

Mass of benzene = 8.600 g

Molar mass of benzene = 78 g/mole

First we have to calculate the moles of benzene.

$\text{Moles of benzene}=\frac{\text{Mass of benzene}}{\text{Molar mass of benzene}}=\frac{8.600g}{78g/mol}=0.1103mole$

Now we have to calculate the energy of combustion.

The given balanced chemical reaction is:

$2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)+6542 kJ$

According to reaction,

As, 2 moles of benzene gives 6542 kJ of energy on combustion.

So, 0.1103 mole of benzene gives $\frac{6542 kJ}{2}\times 0.1103=360.7913kJ$ of energy on combustion.

Now we have to calculate the final temperature of the water.

Formula used : $q_w=m_w\times c_w\times \Delta T=m_w\times c_w\times (T_{final}-T_{initial})$

where,

$q_w$ = heat released = 360.7913 kJ = 36079.13 J

$m_w$ = mass of water = 5691 g

$c_w$ = specific heat of water= $4.18J/g^oC$

$T_{final}$ = final temperature = ?

$T_{initial}$ = initial temperature = $21^oC$

Now put all the given values in the above formula, we get:

$36079.13J=5691g\times 4.18J/g^oC\times (T_{final}-21^oC)$

$T_{final}=22.5166^oC$

Therefore, the final temperature of the water is, $22.5166^oC$

8 0

4 years ago

In nature, oxygen has three common isotopes. The atomic masses and relative abundances of these isotopes are given in the table

Vaselesa [24]

Answer: The average atomic mass of oxygen is 15.999 amu

Explanation:

Mass of isotope O-16 = 15.995 amu

% abundance of isotope O-16= 99.759 % = $\frac{99.759}{100}=0.99759$

Mass of isotope O-17 = 16.995 amu

% abundance of isotope O-17 = 0.037% = $\frac{0.037}{100}=0.00037$

Mass of isotope O-18 = 17.999 amu

% abundance of isotope O-18 = 0.204% = $\frac{0.204}{100}=0.00204$

Formula used for average atomic mass of an element :

$\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})$

$A=\sum[(15.995\times 0.99759)+(16.995\times 0.00037)+(17.999 \times 0.00204)]$

$A=15.999$

Thus the average atomic mass of oxygen is 15.999 amu

5 0

3 years ago

Consider the complete reaction of 43.0 g of silicon with excess nitrogen gas in the reaction shown below. What mass of product f

kupik [55]

The answer to your question is : no.of moles of Si = 43/atomic mass of Si = 43/28.1 = 1.53

according to reaction 3 moles of Si gives 1 mole of Si3N4

so 1.53 mole of Si will give 1.53/3 = 0.51 mole of Si3N4

molar mass of Si3N4 = 140.28 g/mole

it means that 1 mole of Si3N4 = 140.28 g

so 0.51 mole of Si3N4 = 0.51 X 140.28 = 71.543 g

7 0

3 years ago

The _______ force is a noncontact force that is created by the movement of an electrical charge. A. centrifugal B. electromagnet

Nataliya [291]

the answer for your question is B. Electromagnetic. because electric charge is the physical property that causes it to experience force when it is placed in a electromagnetic field the electric charge is carried by subatomic particles which causes the movement of the magnetic force

6 0

3 years ago

Read 2 more answers

A gas occupies 900.0 mL at a temperature of 27.0 ˚C. Assuming constant pressure, what is its volume if it is heated to 132.0 ˚C?

Stella [2.4K]

Answer:

new volume is 1215mL

Explanation:

using Charles law , the volume of a fixed mass of gas is directly proportional to its temperature provide that pressure is kept constant.

$\frac{V1}{T1}=\frac{V2}{T2}$

V1=900mL ,

convert the temperatures from Celsius to kelvin temperature.

T1 =27°C =27+273 =300K

T2 =132°C = 132+273=405K

$V2=\frac{V1T2}{T1}$

$V2=\frac{900*405}{300}$

V2= 1215mL

8 0

4 years ago