I believe it is the 3rd answer choice: 160/3(pi) cm cubed
Answer: A mass of 0.518 g of phenol must be dissolved in 25.0 g of naphthalene to produce a solution that is 0.22 m in phenol.
Explanation:
Given: Mass of naphthalene = 25.0 g
Molality = 0.22 m
This means that 0.22 moles of solute is present per kg of solvent.
As 25.0 g of naphthalene is there that will be 25.0 g per 1000 g (1 kg) is equal to 0.025 kg.
Hence, moles of phenol are calculated as follows.
Also, molar mass of phenol is 94.11 g/mol. This means that 1 mole of phenol contains 94.11 g.
Therefore, mass contained by 0.0055 moles of phenol is as follows.
Thus, we can conclude that a mass of 0.518 g of phenol must be dissolved in 25.0 g of naphthalene to produce a solution that is 0.22 m in phenol.
Protists are NOT prokaryotes so the answer would be B) False.
Answer:
Whenever the two groups on each end of a carbon-carbon double bond are the same, two diastereomers are possible.
Explanation:
Double bonds are formed when four electrons are shared between two carbon atoms. The second bond is generally known as a pi-bond while the first bond is called a sigma bond.
The presence of a double bond in a compound leads to restricted rotation about the carbon-carbon double bond. Hence the substituents are 'locked' in a particular configuration.
The more substituted a double bond is, the more stable it is according to Saytzeff's Rule.
Due to steric effects, trans alkenes are generally more thermodynamically stable than cis alkenes since trans alkenes have bulky groups oriented apart from each other.
All these are true statements. The answer selected must be the untrue statement.
<span>Soln:
•t: in min
•Q(t): quantity of dye in the tank at time t
•r in= 0: rate of dye poured into the tank per min. Since it is fresh water, so it
is zero.
•r out= density of dye×rate of fluid =Q/900×9: rate of dye flowing out.
•Q(0) = 1×900 g: initial amount of dye in the tank.
•{dQ/dt=rin-rout= 0-Q100 Q(0) = 900g•Q(t)=Ce-1/100t
•Q(0) = 900, C= 900, Q(t) = 900e-1/100t
•Q(t) = 0.01·Q(0), Q(0)e-1/100t= 0.01×Q(0),-t100= ln 0.01, t= 460min</span>