<span>0.74 Kcal/min x 1000 cal/60 s
</span>
Answer:

The temperature for ![\Delta G^o=0[/tex is [tex]T=328.6 K](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D0%5B%2Ftex%20is%20%5Btex%5DT%3D328.6%20K)
Explanation:
The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

Where:
is Gibbs's energy in kJ
is the enthalpy in kJ
is the entropy in kJ/K
is the temperature in K
Solving:


For
:





Answer:
130 Liters
Explanation:
if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)
Answer:
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Explanation:
Water potential = Pressure potential + solute potential


We have :
C = 0.15 M, T = 273.15 K
i = 1
The water potential of a solution of 0.15 m sucrose= 
(At standard temperature)


The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.