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2 years ago

Hii I need a tutor for chemistry

Chemistry

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kap26 [50]2 years ago

3 0

Answer:

I had a tutor for chemistry but I think I don't have the number now.

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How many grams of aluminum chloride are produced when 5.96 grams of aluminum are reacted with excess chlorine gas? Start with a

Vadim26 [7]

Answer:

29.47 g of AlCl₃.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Al + 3Cl₂ —> 2AlCl₃

Next, we shall determine the mass of Al that reacted and the mass of AlCl₃ produced from the balanced equation. This can be obtained as follow:

Molar mass of Al = 27 g/mol

Mass of Al from the balanced equation = 2 × 27 = 54 g

Molar mass of AlCl₃ = 27 + (35.5× 3)

= 27 + 106.5

= 133.5 g/mol

Mass of AlCl₃ from the balanced equation = 2 × 133.5 = 267 g

SUMMARY:

From the balanced equation above,

54 g of Al reacted to produce 267 g of AlCl₃.

Finally, we shall determine the mass of AlCl₃ produced by the reaction of 5.96 g of Al. This can be obtained as follow:

From the balanced equation above,

54 g of Al reacted to produce 267 g of AlCl₃.

Therefore, 5.96 g of Al will react to produce = (5.96 × 267)/54 = 29.47 g of AlCl₃.

Thus, 29.47 g of AlCl₃ were obtained from the reaction.

3 0

2 years ago

If an effusion experiment, it required 45 seconds for

patriot [66]

Answer: A vacuum. Under the same conditions 16 s were required for the same number of moles of O2 to effuse. ... The molar mass of the unknown gas is 200 g/mol. calculation ... QUESTION 1 If gas-burning appliances are vented into an unlined masonry chimney, deteriorate and crumble and may · PLS HELP

Explanation:

8 0

3 years ago

Fundamental differences in the cell, the basic unit of life, allow for broadest classification of all living organisms into thre

Nana76 [90]

Answer:

Explanation:

7 0

3 years ago

A 1.04L sample of gas of 759 mm Hg pressure is expanded

Marta_Voda [28]

Answer:

P2 = 352 mm Hg (rounded to three significant figures)

Explanation:

PV = nRT

where P is the pressure,

V is the volume,

n is the moles of gas,

R is the gas constant,

and T is the temperature.

We must relate this equation to a sample of gas at two different volumes however. Looking at the equation, we can relate the change in volume by:

P1V1 = P2V2

where P1 is the initial pressure,

V1 is the initial volume,

P2 is the final pressure,

and V2 is the final volume.

Looking at this relationship, pressure and volume have an indirect relationship; when one goes up, the other goes down. In that case, we can use this equation to solve for the new pressure.

P1V1 = P2V2

(759 mm Hg)(1.04 L) = P2(2.24 L)

P2 = 352 mm Hg (rounded to three significant figures)

8 0

2 years ago

One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of

iogann1982 [59]

Answer:

T₂ = 43.46 °C

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,

$m_{water}\times C_{water}\times \Delta T=Q$

For water:

Mass of water = 5100 g

Specific heat of water = 4.18 J/g°C

T₁ = 25 °C

T₂ = ?

Q = 393500 J

So,

$5100\times 4.18\times (T_2-25)=393500$

T₂ = 43.46 °C

6 0

3 years ago

Hii I need a tutor for chemistry￼

Hii I need a tutor for chemistry