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adelina 88 [10]
3 years ago
11

While getting a beaker from the shelf, robert dropped the beaker and it broke. what should robert do first?

Chemistry
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

Inform his teacher

Explanation:

Lab safety determines that any incident in the lab to be  inform to the instructor so he/she can take the proper approach to the situation.

aleksandr82 [10.1K]3 years ago
3 0
Inform his teacher because if he tries to clean it he mit get glass in his hand
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128.3 grams of methane (CH4) is equal to how many moles of methane
Neko [114]
About 8.0 moles of methane.Number of moles = MassMolar mass.

And thus we get the quotient:

128.3⋅g16.04⋅g⋅mol−1=8.0⋅moles of methane.

Note that the expression is dimensionally consistent, we wanted an answer in moles, and the quotients gives, 1mol−1=11mol=mol as required.

6 0
4 years ago
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What percentage of incoming college students did not consume any alcohol?
Katyanochek1 [597]

Answer:

Approximately 38%

What percentage of incoming students report not drinking at all in the past year? Approximately 38% of incoming college students reported not drinking at all in the past year.

Explanation:

4 0
2 years ago
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
irinina [24]

Answer:

m_{KBr}=6.030gKBr

Explanation:

Hello.

In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:

(T_b-T_b_0)=i*m*K_b

Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:

m=\frac{T_b-T_b_0}{i*K_b}=\frac{(119.3-117.8)\°C}{2*1.48\°C*kg*mol^{-1}}\\  \\m=0.507mol/kg

Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:

n_{KBr}=0.507mol/kg*0.1kg=0.0507mol

Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:

m_{KBr}=0.0507mol*\frac{119g}{1mol} \\\\m_{KBr}=6.030gKBr

Best regards.

3 0
4 years ago
I need a help from this question!!
Alik [6]

Answer:

B

Explanation:

Please take a look at the picture attached for the drawings and structures.

C2H4 is a alkene (C-C double bond). When steam (water) is added, it turns into an alcohol, where the double bond breaks and a (-OH) functional group is attached to one of the Carbons. In this case, C2H4 ethene is turned into ethanol.

When an alcohol undergoes oxidation, primary alcohols turn into aldehyde (-CHO) or carboxylic acids (-COOH). Secondary alcohol turns into ketone. Ethanol is a primary alcohol. And since it later reacts with propanol, it can only form carboxylic acid when it oxidizes. The product in this reaction is ethanoic acid.

Carboxylic acid reacts with alcohol to form an ester (-COO-). the -COOH group from acid combines with the -OH group from alcohol to form an ester bond -COO- while eliminating H2O. Therefore, when propanol undergoes esterification with ethanoic acid, propyl ethanoate is produced. It is the answer of B.

7 0
4 years ago
Which molecular formula is also an empirical formula? <br> 1)C6h6<br> 2)h2o2<br> 3) n2h4<br> 4) n2o5
Vikki [24]
The answer is number 4, N2O5.

Because it can't be divided any further since 2 and 5 do not have a common divisor.
8 0
3 years ago
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