The formula is easy:
Gram formula mass
----------------------------
Emprical Formula
So if we plug in our own numbers,
114.0
--------
57.116
We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.
2(C4H9) becomes C8H18.
Our molecular formula is C8H18.
Hope I could help!
In order to become a scientific theory the three
categories that it must pass are the following:
1) Can the phenomena be recreated in a laboratory setting?
2) Can variables be changed, yet still result in like observations?
3) Is the phenomena truly natural or was it the result of a man-made force
enacting upon it?
<span>We look at the end of the day:
n(HNO3) added = 0.500*17.0/1000 = 0.00850 mol
n(NH3) = 0.200*75.0/1000 - 0.00850 = 0.00650 mol
[NH3] left = 0.00650*1000/(17.0+75.0) = 0.070652
M [OH-] = Kb * [NH3] = 0.070652*1.8*10^(-5) = 1.27174 x 10^(-6)
pOH = -log[OH-] ≈ 5.8956 pH = 14 - pOH ≈ 8.10</span>
<u>Answer:</u> The molality of solution is 0.740 m.
<u>Explanation:</u>
To calculate the mass of solvent (water), we use the equation:
Volume of water = 750 mL
Density of water = 1 g/mL
Putting values in above equation, we get:
To calculate the molality of solution, we use the equation:
Where,
= Given mass of solute 
= 100.0 g
= Molar mass of solute = 180 g/mol
= Mass of solvent (water) = 750 g
Putting values in above equation, we get:
Hence, the molality of solution is 0.740 m.
Answer:
15.98 L
Explanation:
First, you need to find T1, T2, V1 and V2.
T1 = 25 C = 298.15 K (25C + 273.15K)
T2 = 100 C = 373.15 K (100C + 273.15K)
V1 = 20. L
V2 = ? (we are trying to find)
Next, rearrange to fit the formula
V2 = V1 x T1 / T2
Next, fill in with our numbers
V2 = 20. L x 298.15 K / 373.15 K
Do the math and you should get...
15.98 L
- If you need more help or futher explanation please let me know. I would be glad to help!
