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3 years ago

Reducing access to waterways will lead to an increase in human impact on waterways. T/F

Physics

2 answers:

kirill [66]3 years ago

8 0

Answer: False

A waterway refers to a water body that can be used for the transportation by human population. These includes rives, oceans, lakes, estuary and canals. A waterway should be wide and deep enough to allow the movement of water transportation vehicles like boats and ships. Water transportation is responsible for contaminating the water of waterways. As, the water transportation vehicles releases residues of fuel in the water, which deteriorate the quality of water and makes it unfit for survival of aquatic animal and plant species.

Hence, excess to waterways should be reduced in order to prevent water pollution. Reducing access to waterways will lead to decrease in human impact on waterways.

Therefore, the statement reducing access to waterways will lead to an increase in human impact on waterways is false.

vlada-n [284]3 years ago

3 0

The answer is false. It will decrease human impact due to access being reduced. It sounds like a trick question, but it's not. It is very straight forward. False is your answer young padawan.

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Glaciers store about 72% of the world's freshwater false are true

IRISSAK [1]

The answer to this question is True.

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3 years ago

A solar panel is used to recharge a battery. The solar panel produces 0.80 W of electrical power. The panel is 20% efficient. Wh

Vlad [161]

Answer:

Input power, Ip = 4 Watts

Explanation:

Given the following data;

Power output = 0.8 Watts

Efficiency = 20%

To find the power input of the sunlight onto the solar panel;

Mathematically, the efficiency of a machine is given by the formula;

$Efficiency = \frac {Out-put \; power}{In-put \; power} * 100$

Substituting into the formula, we have;

$20 = \frac {0.8}{Ip} * 100$

$20 = \frac {80}{Ip}$

Cross-multiplying, we have;

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Input power, Ip = 4 Watts

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3 years ago

Shelley is in an elevator that is traveling downward and slowing down at a rate of

liraira [26]

Answer:

N = 648.55[N]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F = Forces applied [N]

m = mass = 73.2 [kg]

a = acceleration = 0.950 [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

$-m*g + N = -m*a\\$

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force (or weight) measured by the scale = 83.4 [N]

Now replacing:

$-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N]$

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

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3 years ago

A body is traveling at 5.0 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion s

loris [4]

To solve this problem it is necessary to apply the concepts related to the conservation of momentum and conservation of kinetic energy.

By definition kinetic energy is defined as

$KE = \frac{1}{2} mv^2$

Where,

m = Mass

v = Velocity

On the other hand we have the conservation of the moment, which for this case would be defined as

$m*V_i = m_1V_1+m_2V_2$

Here,

m = Total mass (8Kg at this case)

$m_1=m_2 =$ Mass each part

$V_i =$ Initial velocity

$V_2 =$ Final velocity particle 2

$V_1 =$ Final velocity particle 1

The initial kinetic energy would be given by,

$KE_i=\frac{1}{2}mv^2$

$KE_i = \frac{1}{2}8*5^2$

$KE_i = 100J$

In the end the energy increased 100J, that is,

$KE_f = KE_i KE_{increased}$

$KE_f = 100+100 = 200J$

By conservation of the moment then,

$m*V_i = m_1V_1+m_2V_2$

Replacing we have,

$(8)*5 = 4*V_1+4*V_2$

$40 = 4(V_1+V_2)$

$V_1+V_2 = 10$

$V_2 = 10-V_1$ (1)

In the final point the cinematic energy of EACH particle would be given by

$KE_f = \frac{1}{2}mv^2$

$KE_f = \frac{1}{2}4*(V_1^2+V_2^2)$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$ (2)

So we have a system of 2x2 equations

$V_2 = 10-V_1$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$

Replacing (1) in (2) and solving we have to,

200J=\frac{1}{2}4*(V_1^2+(10-V_1)^2)

PART A: $V_1 = 10m/s$

Then replacing in (1) we have that

PART B: $V_2 = 0m/s$

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3 years ago

How does torque of rotating body relate to velocity

Fudgin [204]

Answer:

We know that the torque can be calculated as follows:

T = rpsinα

With r being the distance of the body from the center of the circumference he has as trajectory, p being the momentum of the body and sinα being the sine of the angle between the 2 vectors: r and p.

It's pretty obvious that T is directly proportional to the momentum, that can be written as p = m·v, with m being the mass of the object and v the velocity of the object.

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3 years ago