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In-s [12.5K]
3 years ago
15

For the linear function ƒ(x) = 7x – 4, find the range of ƒ(x) at x = –2, 0, and 2.

Mathematics
1 answer:
Tomtit [17]3 years ago
5 0

Answer:range is -2

Step-by-step explanation:

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The base of an isosceles triangle is parallel to the x-axis. The y-axis passes through an end point of the base. If the endpoint
AnnyKZ [126]
The first x coordinate is given by 0 and the second one is given as j. So the length of the base is j. (Sometimes in math they give letters rather than numbers. And since you know it is an isosceles then the other vertex should be at x-coordinate half j or j/2.
5 0
2 years ago
Angle A and angle B are supplementary angles, if angle B equals 73°, what is the measurement of angle A?
balandron [24]
Supplementary means adds to 180
A+B=180
B=73
A+73=180
minus 73 both sides
A+73-73=180-73
A+0=107
A=107

A=107 degrees
7 0
2 years ago
Read 2 more answers
You have 350 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river
IrinaVladis [17]

The length and width that will maximize the area are 175 ft and 87.5 ft respectively

The largest area that can be enclosed is 15312.5 ft²

<h3>Area of a rectangle</h3>
  • area = lw

where

l = length

w = width

The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.

Therefore,

perimeter = l + 2w

350 = l + 2w

l = 350 - 2w

area = (350 - 2w)w

(350 - 2w)w = 0

where

w = 0 or 175

average = 175/2 = 87.5

Hence, the max area is at w = 87.5 ft

Therefore,

l = 350 - 2(87.5) = 175 ft

length = 175 ft

width =  87.5 ft

Therefore,

area = 175 × 87.5 = 15312.5 ft²

Therefore, the largest area that can be enclosed is 15312.5 ft²

learn more on rectangle here: brainly.com/question/11630499

4 0
2 years ago
Let g(x) = 2x2 - 11x. Find g(-1).<br> A) -13 Eliminate <br> B) -9 <br> C) 0 <br> D) 13
worty [1.4K]

Solution

g(x) = 2x^{2} - 11x

Plugging in x = -1 in g(x), we get

g(-1) = 2(-1)^{2} - 11(-1)

Now we have to simplify it.

g(-1) = 2*1 + 11

g(-1) = 2 + 11

g(-1) = 13

So the answer is D) 13.


Thank you. :)

3 0
3 years ago
In how many ways can 5 different novels, 4 different mathematics books, and 1 biology book be arranged on a bookshelf if: (a) Th
Zinaida [17]

Answer:

(a) 3628800 ways

(b) 17280 ways

(c) 120960 ways

Step-by-step explanation:

Given

Novels = 5

Maths = 4

Biology = 1

Total = 10

Solving (a): Arrangement with no restriction.

We simply count each book with no restriction. i.e. 10 books

So, the number of arrangement is:

Arrangement =10!

Arrangement =10*9*8*7*6*5*4*3*2*1

Arrangement =3628800

Solving (b): Maths book together and Novels together

First, arrange the 4 maths books as:

Maths = 4!

Next, arrange the 5 novels as:

Novels = 5!

Lastly, take the 4 maths book as [1], the 5 novels as [1] and the remaining [1] biology book.

So, we have: 3 books

Arrange 3 books, we have:

Books = 3!

Total arrangement is:

Total = 4! * 5! * 3!

Total = 4*3*2*1 * 5*4*3*2*1 * 3*2*1

Total = 17280

Solving (c): Maths book together

First, arrange the 4 maths books as:

Maths = 4!

Next, take the 4 maths book as [1], then the remaining 6 books (i.e. 5 novels and 1 biology)

So, we have: 7 books

Arrange 7 books, we have:

Books = 7!

Total arrangement is:

Total = 4! * 7!

Total = 4*3*2*1 * 7*6*5*4*3*2*1

Total = 120960

7 0
3 years ago
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