Lyman Series Working Formula:
1/λ = RH (1-(1/n^2))
Given:
n = 6
RH = Rydberg's constant = 1.0968x10^7 m^-1
c = speed of light = 3x10^8 m/s
Required:
Frequency (Hertz or cycles per second)
Solution:
To solve for the wavelength λ, we substitute the given in the working formula
1/λ = RH (1-(1/n^2))
1/λ = 1.0968x10^7 m^-1 (1-(1/6^2))
λ = 0.0000000938 m or 93.8 nm
To get the frequency, we will use the formula below.
f = c/λ
We then substitute c or the speed of light,
f = (3x10^8 m/s) / 0.0000000938 m
Therefore,
f = 3.2x10^15 s^-1
<em>ANSWER: Frequency = </em><em /><em>3.2x10^15 s^-1</em>
а о
Explanation:
The given cation:
(Rf₂Al₂F₃)³⁺
The oxidation number gives the extent to which a specie is oxidized in a reaction.
This number is assigned based on some rules:
- Elements in combined state whose atoms combines with themselves have an oxidation number of zero.
- The charge carried on simple ions gives their oxidation number.
- Algebraic sum of all the oxidation numbers of atoms in neutral compound is zero. In an ion with more than one kind of atom, the charge on it is the oxidation number.
for the specie given;
Known:
oxidation number of Al = +3
F = -1
charge = +3
let the oxidation number of Rf = k
2k + 2(3) + 3(-1) = +3
2k + 6 - 3 = 3
2k = 0
k = 0
The oxidation state of rutherfodium is 0
learn more:
Oxidation state brainly.com/question/10017129
#learnwithBrainly
Explanation:
Isopropyl alcohol is the solvent used in whiteboard markers. When it comes into contact with the permanent marker, the solvent breaks the cohesive force between the ink molecules and the whiteboard by solubilising them (i.e. returning them to solution).
C.354
1L/1000cm^3
0.354L/ycm^3 *1L/1000cm^3
Cross multiply 0.354 by 1000and then divide by one to get 354.
Answer:
Percent yield = 7.1%
Explanation:
The general reaction of the problem is:
Ca(OH)₂ + CO₂ → H₂O + CaCO₃
To solve this question we need to find theoretical yield using the amount of carbon dioxide added because:
Percent yield = Actual yield (3.22g) / Theoretical yield * 100
Theoretical yield is the maximum amount of product that could be obtained. To find it we need to convert the mass of CO₂ to moles. The moles of CO₂ = Moles of CaCO₃:
<em>Moles CO₂ -Molar mass: 44.01g/mol):</em>
20.0g * (1mol / 44.01g) = 0.454 moles CO₂ = Moles of CaCO₃ produced
<em>Mass CaCO₃ = Theoretical yield -Molar mass: 100.09g/mol-:</em>
0.454 moles * (100.09g / mol) = 45.5g of CaCO₃ = Theoretical yield.
Replacing:
Percent yield = 3.22g / 45.5g * 100
<h3>Percent yield = 7.1%</h3>