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3 years ago

How does molecular size affect solubility

Chemistry

1 answer:

VashaNatasha [74]3 years ago

4 0

the larger the molecules of the solute are, the larger is their molecular weight and their size.

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Write the net ionic equation for this reaction occurring in water: ammonium fluoride and magnesium chloride are mixed to form ma

MAXImum [283]

Correct answer: 3. $Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)$

The given chemical reaction is between ammonium fluoride and magnesium chloride to form magnesium fluoride and ammonium chloride.

The balanced chemical equation representing the reaction will be,

$2NH_{4}F (aq) + MgCl_{2}(aq) -->MgF_{2} (s) + 2NH_{4}Cl (aq)$

The complete ionic equation for the reaction: All the compounds soluble in water (aqueous) will split into ions, $MgF_{2}$ will not split into ions as it is insoluble in water.

$2 NH_{4}^{+}(aq) + 2 F^{-}(aq) + Mg^{2+}(aq) + 2 Cl^{-}(aq) --> MgF_{2}(s) + 2 NH_{4}^{+}(aq) + 2 Cl^{-}(aq)$

The net ionic equation will be:

$Mg^{2+}(aq) + 2 F^{-}(aq) --> MgF_{2}(s)$

Here the spectator ions are $NH_{4}^{+} and Cl^{-}$

6 0

3 years ago

Which of the following causes the formation of ionic bonds

pantera1 [17]

Answer: b. One atom transferring electrons to another atom

Explanation: An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element and the element which accepts the electrons is known as electronegative element. This bond is formed between a metal and an non-metal.

Covalent bonds are formed by sharing of electrons between non metals

For example, In calcium iodide the one electron from calcium metal gets transferred to iodine atom and thus form an ionic bond to give $CaI_2$

Electronic configuration of calcium:

$[Ca]=1s^22s^22p^63s^23p^64s^2$

Calcium atom will lose two electron to gain noble gas configuration and form calcium cation with +2 charge.

$[Ca^{2+}]=1s^22s^22p^63s^23p^6$

Electronic configuration of iodine:

$[I]=1s^22s^22p^63s^23p^64s^23d^{10}4p^5$

Iodine atom will gain one electron to gain noble gas configuration and form iodide ion with -1 charge.

$[I^-]=1s^22s^22p^63s^23p^64s^23d^{10}4p^6$

7 0

3 years ago

The oxidation of magnesium to form magnesium oxide is shown by which balanced chemical equation?

il63 [147K]

magnesium oxide is: MgO (right side)

so the left side is: Mg + O2

for the equation to be balanced there must be two oxygens on both sides

Mg + O2 = 2MgO

but now the magnesium is uneven, so there must be two magnesiums on each side

the answer is: B) 2Mg + O2 = 2MgO

5 0

3 years ago

Read 2 more answers

A 24.00 mL sample of a solution of Pb(ClO3)2 was diluted with water to 52.00 mL. A 17.00 mL sample of the dilute solution was fo

klio [65]

Answer:

0.238 M

Explanation:

A 17.00 mL sample of the dilute solution was found to contain 0.220 M ClO₃⁻(aq). The concentration is an intensive property, so the concentration in the 52.00 mL is also 0.220 M ClO₃⁻(aq). We can find the initial concentration of ClO₃⁻ using the dilution rule.

C₁.V₁ = C₂.V₂

C₁ × 24.00 mL = 0.220 M × 52.00 mL

C₁ = 0.477 M

The concentration of Pb(ClO₃)₂ is:

$\frac{0.477molClO_{3}^{-} }{L} \times \frac{1molPb(ClO_{3})_{2}}{2molClO_{3}^{-}} =0.238M$

4 0

3 years ago

To break the oxygen-oxygen bonds in a single O2 molecule, 1 × 10–18 J of energy is required. Which of the following wavelengths

Sonbull [250]

E = hc/(lamda)

The lamda symbol is wavelength, which this site does not have. I can represent it with an "x" instead.

Plancks constant, h = 6.626×10^-32 J·s

Speed of light, c = 3.00×10^8 m/s

The energy must be greater than or equal to 1×10^-18 J

1×10^-18 J ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / x

x ≤ (6.626×10^-32 J·s)*(3.0×10^8 m/s) / (1×10^-18 J)

x ≤ 1.99×10^-7 m or 199 nm

The wavelength of light must be greater than or equal to 199 nm

8 0

3 years ago