The vectors adition we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction
Parameters given
- Force of an astronaut Fₓ = 42 N
To find
The force is a vector magnitude for which the addition of vectors must be used, a very efficient method to perform this sum is to add the components of each vector and devise constructing the resulting vector using trigonometry and the Pythagorean theorem.
Let's use trigonometry to find the other force
tan θ =
F_ y = Fₓ tan θ
let's calculate
F_y = 42 tan 15
F_y = 11.25 N
Using the summation of vectors we can find the magnitude of the force applied by the other astronaut is 11.25 N in the y direction
Learn more about vector addition here:
brainly.com/question/15074838
Answer:
v=32.49 m/s
Explanation:
Given that
Distance ,d= 66 m
Initial speed of the car ,u = 0 m/s
Coefficient of friction ,μ = 0.8
Lets take the total mass of the car = m
The acceleration of the car is given as
a = μ g ( g= 10 m/s² )
Now by putting the values in the above equation we get
a= 0.8 x 10 m/s²
a= 8 m/s²
We know that ,final speed is given as
v²= u ²+ 2 a d
Now putting the value
v²=0² + 2 x 8 x 66
v²= 1056
v=32.49 m/s
Answer:
Newton's third law.
Explanation:
•your hand of holding UP/DOWN the cup has a reaction with force
•Coffee inside the cup is pushing outward to the edges of the cup
•The cup is pushing inward onto the coffee
"His third law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A."
The answer is false, your welcome.
- Kinetic Energy of an object is the measure of the work an object can do by virtue of its motions..
- Where KE is the kinetic energy, m is the body’s mass, and v is the body’s velocity.
- Potential energy is the stored energy in any object or system by virtue of its position or arrangement of parts..
Where,
. m is the mass in kilograms
. g is the acceleration due to gravity
. h is the height in meters
Hope it helpz~ uh..