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EleoNora [17]
3 years ago
10

Two identical peaches, Peach 1 and Peach 2, fall from a cliff at time t=0t=0t, equals, 0 from the same height. Peach 1 is droppe

d from rest, while Peach 2 is thrown horizontally.
Which graph best describes the vertical displacement of Peach 1 and 2 over time?
Assume the origin of the coordinate system to be the cliff edge.
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
A graph is shown with the vertical axis labeled y and the horizontal axis labeled t. Two lines both start at the origin and slope downwards to the right. The solid line is straight while the dashed line has downward concavity.

(Choice B)
B
A graph is shown with the vertical axis labeled y and the horizontal axis labeled t. Two lines both start at the origin and slope downwards to the right. The dashed line is straight while the solid line has upward concavity.

(Choice C)
C
A graph is shown with the vertical axis labeled y and the horizontal axis labeled t. Two lines both start at the origin and slope downwards to the right with downward concavity. Both lines are coincident.

(Choice D)
D
A graph is shown with the vertical axis labeled y and the horizontal axis labeled t. Two lines both start at the origin and slope downwards to the right with downward concavity. The solid line is shallower than the dashed line.

(Choice E)
E
A graph is shown with the vertical axis labeled y and the horizontal axis labeled t. Two lines both start at the origin and slope downwards to the right with upward concavity. The dashed line is shallower than the solid line.
Report a problem
4 of 9
Physics
2 answers:
Alik [6]3 years ago
5 0

Answer: it C

Explanation:

Hunter-Best [27]3 years ago
4 0

Answer: The correct answer is graph A.

Explanation:

See Khan Academy.

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Mike walks 200 km in 6 hours.he then walks another 100km in 4 hours .what is his average speed?
kolbaska11 [484]

Average speed is defined as the ratio of total distance covered in total given time

speed = \frac{distance}{time}

here we know that total distance that man moved is

d_1 = 200 km

d_2 = 100 km

so total distance is

d = d_1 + d_2

d = 200 km + 100 km

d = 300 km

now here total time of the motion is

t_1 = 6 hours

t_2 = 4 hours

total time will be given as

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t = 6 + 4 = 10 hours

now by above formula

v_{avg} = \frac{300}{10}

v_{avg} = 30 km/h

so his average speed is 30 km/h

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A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function
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Integrating the velocity equation, we will see that the position equation is:

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<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$v(t)=\sin (\omega t) * \cos ^2(\omega t)

To get the position equation we just need to integrate the above equation:

$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t

$\mathrm{u}=\cos (\omega \mathrm{t})

Then:

$d u=-\sin (\omega t) d t

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Replacing that in our integral we get:

$\int \sin (\omega t) * \cos ^2(\omega t) d t$

$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$

Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$f(t)=\frac{\cos ^3(\omega t)}{3}+C

To find the value of C, we use the fact that f(0) = 0.

$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0

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Then the position function is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

Integrating the velocity equation, we will see that the position equation is:

$f(t)=\frac{\cos ^3(\omega t)-1}{3}

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When the incident light is yellow the width of the central band greater. Single-wavelength light sources are known as monochromatic lights, where mono stands for one and chroma for color. Monochromatic lights are defined as visible light that falls inside a specific range of wavelengths. It has a wavelength that falls within a constrained wavelength range.

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What happens when two positive charges are near each other?
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If two positive charges are near each other they will repel each other.
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