Question

At Hoover Dam, the distance the water effectively falls before encountering the electric generators depends on the water levels in Lake Mead. Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas lightbulbs for 6.0 minutes? (HINT: This is a conservation of energy problem. All the energy comes from the falling water. Consider the electric generators to be 100% efficient.) Give your answer in kilograms, and enter your answer in the format *.**E**. kg To imagine how much water this is, recall that 1.0 kg of water occupies a volume of 1.0 liter.

Answer 1

Answer:

Explanation:

recall that power is energy carried out or work done per time

P=W/t

P=2*10^6*35

t=6*60=420S

W=Energy

E=2*10^6*35*360S

E=25200000000

Energy stored by water from rest is called potential energy. Since the water is falling from a height , we calculate potential energy as thus

E=M*g*h

Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas light bulbs for 6.0 minutes?

M=mass of water

g=acceleration due to gravity 9.81m/s^2

h=height ,175m

25200000000=M*9.81*175

M=$\frac{25200000000}{175*9.81}$

M=1716.75kg