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VashaNatasha [74]
3 years ago
11

At Hoover Dam, the distance the water effectively falls before encountering the electric generators depends on the water levels

in Lake Mead. Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas lightbulbs for 6.0 minutes? (HINT: This is a conservation of energy problem. All the energy comes from the falling water. Consider the electric generators to be 100% efficient.) Give your answer in kilograms, and enter your answer in the format *.**E**. kg To imagine how much water this is, recall that 1.0 kg of water occupies a volume of 1.0 liter.
Physics
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

Explanation:

recall that power is energy carried out or work done per time

P=W/t

P=2*10^6*35

t=6*60=420S

W=Energy

E=2*10^6*35*360S

E=25200000000

Energy stored by water from rest is called potential energy. Since the water is falling from a height , we calculate potential energy as thus

E=M*g*h

Assume that the water intakes are effectively 175 m above the electric generators. How much water must pass through the generators to power 2 million 35-W Las Vegas light bulbs for 6.0 minutes?

M=mass of water

g=acceleration due to gravity 9.81m/s^2

h=height ,175m

25200000000=M*9.81*175

M=\frac{25200000000}{175*9.81}

M=1716.75kg

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A tensile test specimen has a gage length = 50 mm and its cross-sectional area = 100 mm2. The specimen yields at 48,000 N, and t
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Answer:

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b) modulus of elasticity

strain calculation

\varepsilon_0=\dfrac{L-L_0}{L_0}=\dfrac{50.23-50}{50} = 0.0046

strain for offset yield point

\varepsilon_{new} = \varepsilon_0 -0.002

                              =0.0046-0.002 = 0.0026

now, modulus of elasticity

 E = \dfrac{\sigma_y}{\varepsilon_{new}}=\dfrac{480}{0.0026}

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c) tensile strength

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d) percentage elongation

\% Elongation = \dfrac{L-L_0}{L_0}\times 100 = \dfrac{67.3-50}{50}\times 100 = 34.6\%

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\% Area\ reduction = \dfrac{A-A_f}{A}\times 100=\dfrac{100-53}{100}= 47 \%                            

7 0
3 years ago
Calculate the mass (in g) of 346 cm³ of polythene. The density of polythene is 0.95 g/cm³. Give your answer to 2 decimal places.
IceJOKER [234]

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

Solve:

M = <u>(95×346)</u>

10

= <u>3</u><u>2</u><u>8</u><u>7</u><u>0</u>

100

M = 328.70g

8 0
2 years ago
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3 0
3 years ago
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Consider a venturi with a small hole drilled in the side of the throat. This hole is connected via a tube to a closed reservoir.
Marina CMI [18]

Answer:

(P_1-P_2)=1913.31 N/m^2

Explanation:

given:

\frac{A_t}{A_1}=0.85

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solution:

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6 0
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