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GREYUIT [131]
3 years ago
10

Calculate how much work you need to move the 130 N trunk to a ledge 2 m above.

Physics
2 answers:
kupik [55]3 years ago
8 0
Formula for the work is
W=Fs
where F is force and s is distance
Now we can just substitute our data and find work
W=130N*2m=260J
The result is 260J.
vaieri [72.5K]3 years ago
4 0
The absolute minimum work required for that job is the potential energy that will be added to the trunk by moving it up 2meters.

Potential energy = (weight) x (height) = (130 N) x (2) = <em>260 Joules</em>

That's the absolute minimum, because the trunk itself needs that much
energy in order to get up there.  But if you're doing the lifting, you may need
to expend more energy than that, just because the human body is not a
100% efficient machine.  It always takes more work to do something physical
than the energy you actually deliver to the job.

Here's a mind-blowing factoid: 
Do you see that 260 joules up there in the answer to the trunk ?
If you eat, let's say, 1800 Calories a day and don't gain any weight, that means
that you're burning off 260 joules of energy about every 3 seconds ! ! ! 
Just to keep your body warm, keep your breathing going, keep your brain
in tune, and move yourself around !  
Enough energy to lift that 30-pound trunk about 6-1/2 feet straight up off
the floor !


1 Calorie = 4184 joules
1 day = 86,400 seconds
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Molecular orbital theory correctly predicts paramagnetism of oxygen gas. true or false
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Answer: Yes.

Explanation:

Oxygen has a bond order of two. The bond order of Oxygen molecule is calculated, where the [<em>eight valence electrons in bonding molecular orbitals</em> minus (-) <em>four valence electrons in antibonding molecular orbitals</em>]/2 in the electron configuration.

Atoms/molecules where electrons are paired are diamagnetic (repelled by both poles of a magnetic); while atoms/molecules that have one or more unpaired electrons are paramagnetic (attracted to magnetic field).

The two unpaired electrons of dioxygen molecules has made it <u>paramagnetic</u>. By pouring liquid oxygen between the poles of a strong magnet, the liquid stream will be contained by the filed and fills up the space between the poles.

3 0
3 years ago
If your hood suddenly flies up, which of the following should you avoid?
seraphim [82]
The answer is 4. accelerating to move off the road as quickly as possible
3 0
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You may make the following measurements of an object 42kg and 22m3. What would the objects density be?
ki77a [65]
Density=mass/volume
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8 0
3 years ago
Calculate the wavelengths of the first five members of the Lyman series of spectral lines, providing the result in units Angstro
Oduvanchick [21]

Answer:

Explanation:

The formula for hydrogen atomic  spectrum is as follows

energy of photon due to transition from higher orbit n₂ to n₁

E=13.6 (\frac{1}{n_1^2 } - \frac{1}{n_2^2})eV

For layman series n₁ = 1 and n₂ = 2 , 3 , 4 ,   ...   etc

energy of first line

E_1=13.6 (\frac{1}{1^2 } - \frac{1}{2 ^2})

10.2 eV

wavelength of photon = 12375 / 10.2 = 1213.2 A

energy of 2 nd line

E_2=13.6 (\frac{1}{1^2 } - \frac{1}{3 ^2})

= 12.08 eV

wavelength of photon = 12375 / 12.08 = 1024.4 A

energy of third line

E_3=13.6 (\frac{1}{1^2 } - \frac{1}{4 ^2})

12.75 e V

wavelength of photon = 12375 / 12.75 = 970.6 A

energy of fourth line

E_4=13.6 (\frac{1}{1^2 } - \frac{1}{5 ^2})

= 13.056 eV

wavelength of photon = 12375 / 13.05 = 948.3 A

energy of fifth line

E_5=13.6 (\frac{1}{1^2 } - \frac{1}{6 ^2})

13.22 eV

wavelength of photon = 12375 / 13.22 = 936.1 A

7 0
3 years ago
A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
Anastaziya [24]

Answer:

The gauge pressure is  P_g  =  2058 \ P_a

Explanation:

From the question we are told that

       The height of the water contained is  h_w  =  30 \ cm  =  0.3 \ m

        The height of liquid in the cylinder is  h_t  =  40 \ cm  = 0.4 \ m

       

At the bottom of the cylinder the gauge pressure is  mathematically represented as

        P_g  =  P_w + P_o

Where  P_w is the pressure of water which is mathematically represented as

      P_w  =  \rho_w  *  g * h_w

Now  \rho_w is the density of water with a constant values of  \rho_w  = 1000 \ kg /m^3

   substituting values

      P_w  = 1000 *  9.8 *  0.3

     P_w  =  2940 \  Pa

While P_o is the pressure of oil which is mathematically represented as

          P_o  =  \rho_o *  g *  (h_t -h_w )

Where \rho _o is the density of oil with a constant value

         \rho _o  = 900 \ kg / m^3

substituting values

       P_o  =  900 *  9.8 * (0.4 - 0.3)

       P_o  =  882 \ Pa

Therefore

      P_g  =  2940 - 882

      P_g  =  2058 \ P_a

6 0
3 years ago
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