Answer:
5 N
Explanation:
The bucket is moving at a constant speed of 2m/s Therefore F=ma is 0 N for this to be correct the magnitude of the force exerted by the rope must be equal to the weight of the bucket which is 5 N
Y no me digas nada que te lo digo yo no te quiero ni no su what y el de la selección nacional de la selección de
I think they can use more durable materials.
Answer:
the distance in meters traveled by a point outside the rim is 157.1 m
Explanation:
Given;
radius of the disk, r = 50 cm = 0.5 m
angular speed of the disk, ω = 100 rpm
time of motion, t = 30 s
The distance in meters traveled by a point outside the rim is calculated as follows;
![\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Comega%20t%5C%5C%5C%5C%5Ctheta%20%3D%20%28100%20%5Cfrac%7Brev%7D%7B%5Cmin%7D%20%20%5Ctimes%20%5Cfrac%7B2%5Cpi%20%5C%20rad%7D%7B1%20%5C%20rev%7D%20%5Ctimes%20%5Cfrac%7B1%5Cmin%7D%7B60%20s%7D%20%29%20%5Ctimes%20%2830%20s%29%5C%5C%5C%5C%5Ctheta%20%3D%20100%20%5Cpi%20%5C%20rad%5C%5C%5C%5Cd%20%3D%20%5Ctheta%20r%5C%5C%5C%5Cd%20%3D%20100%5Cpi%20%20%5C%20%5Ctimes%20%5C%200.5m%5C%5C%5C%5Cd%20%3D%2050%20%5Cpi%20%5C%20m%20%3D%20157.1%20%5C%20m)
Therefore, the distance in meters traveled by a point outside the rim is 157.1 m
Answer:
51.85m/s
Explanation:
Given parameters:
Mass of ball = 0.0459kg
Force = 2380N
Time taken = 0.001s
Unknown:
Speed of the ball afterwards = ?
Solution:
To solve this problem, we use Newton's second law of motion:
F = m x
F is the force
m is the mass
v is the final velocity
u is the initial velocity
t is the time taken
2380 = 0.0459 x
0.0459v = 2.38
v = 51.85m/s