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lora16 [44]
3 years ago
15

Which nuclear decay emission consists of energy, only?

Chemistry
2 answers:
Sauron [17]3 years ago
6 0
(3) gamma radiation It is Electromagnetic energy only
kow [346]3 years ago
4 0

Answer:  (3) gamma radiation

Explanation:

An isotope can decay in 4 process:

1.) Alpha decay: In this process, alpha particles is emitted when a heavier nuclei decays into lighter nuclei. The alpha particle released has a charge of +2 units.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}+_2^4\alpha

2.)Beta-decay: In this process, a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

3.) Gamma ray emission: in this process, an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral.

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

4.) Positron decay: In this process, a proton gets converted to neutron and an electron neutrino and releases positron particles. This particle carries a charge of +1 units.

_Z^A\textrm{X}\rightarrow _{Z-1}^A\textrm{Y}+_{+1}^0e

In the question, it is given that when an isotope decays, it emits only energy. It is released when an isotope undergoes gamma decay and therefore, the correct answer is gamma radiation.

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A hot air balloon can have a volume of 2950 cubic meters (2.95 ✕ 106 liters) and operate at temperatures up to 250°F (121°C). As
TiliK225 [7]

Answer:

2.64 × 10⁶ g

Explanation:

We can find the mass of air using the ideal gas equation.

P.V=n.R.T=\frac{m}{M} .R.T

where,

P is the pressure (P = 1.00 atm)

V is the volume (V = 2.95 × 10⁶ L)

n is the number of moles

R is the ideal gas constant (0.08206atm.L/mol.K)

T is the absolute temperature (121°C + 273 = 394 K)

m is the mass

M is the molar mass (28.09 g/mol)

m=\frac{P.V.M}{R.T} =\frac{1.00atm \times 2.95 \times 10^{6} L \times 28.97g/mol}{(0.08206atm.L/mol.K) \times 394 K } =2.64 \times 10^{6} g

7 0
3 years ago
Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium
Inessa [10]

Answer:

Gd(g) → Gd^{+}(g) + e^{-} , Gd^{+}(g)→ Gd^{2+}(g) + e^{-}, Gd^{2+}(g) → Gd^{3+}(g) + e^{-}

Explanation:

Ionization energy is the energy required to remove an electron from a gaseous atom or ion.

The first ionization energy is the energy required to remove the valence electron(outermost) from a neutral atom:

Gd(g)→ Gd^{+}(g) + e^{-}

The second ionization energy is the energy required to remove next/second electron from x^{+} ion. The second ionization energy is always higher than the first:

Gd^{+}(g) → Gd^{2+}(g) + e^{-}

The third ionization energy is the energy required to remove third electron from x^{2+} ion:

Gd^{2+}(g) → Gd^{3+}(g) + e^{-}  

5 0
3 years ago
Is barium peroxide Ba2O2 or BaO2?
vredina [299]

Answer:options?

Explanation:

6 0
3 years ago
Read 2 more answers
A sample of gas occupies 1.2 L at 12.0oC. Assuming pressure remains the same, what would be the volume (in L) of this gas at 67o
liraira [26]
V1/T1 = V2/T2
V1 = 1.2 L
T1 = 12.0 + 273 = 285 K
T2 = 67.0 +273 = 340 K

1.2/285 = V2 / 340
V2 = 1.4 L
3 0
3 years ago
What forms when iron-53 decays?
erastovalidia [21]
It depends on the type of decay that's taking place, but if it's b+ it'd decay into Mn-52. If it's b- it'd decay into Co-59 (i'm sure??)
7 0
3 years ago
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