PV = nRT —> P = nRT/V
n = 0.250 moles of gas
R = 0.08206 L atm / mol K
T = 18 + 273 = 291 K
V = 7.50 L
P = (0.250)(0.08206)(291)/(7.50) = 7.96 atm
Answer:
Its pressure will be 0.54 atm at 100 K.
Explanation:
Gay-Lussac's law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of collisions with the walls increases, that is, the pressure increases. That is, the pressure of the gas is directly proportional to its temperature.
Gay-Lussac's law can be expressed mathematically as the quotient between pressure and temperature equal to a constant:

Studying two different states, an initial state 1 and a final state 2, it is satisfied:

In this case:
- P1= 1.75 atm
- T1= 50 °C= 323 K (being 0 C=273 K)
- P2= ?
- T2= 100 K
Replacing:

Solving:

P2= 0.54 atm
<u><em>Its pressure will be 0.54 atm at 100 K.</em></u>
<span>The net ionic equation for the reaction of alum (KAl(SO4)2.12H2O.) and KOH is </span>the solid AlOH3 formed.
The correct answer is - intrusive rocks.
The intrusion is a process in which the rising magma in the Earth's crust, manages to break through pre-existing layers of rock, and after that cool off, solidify, and create new intrusive igneous rocks. By doing so, the magma is breaking up the layers of rocks, thus the intrusive igneous rocks that are forming from it, come to be inside totally different rock units. The intrusions are always happening inside the crust, and the rocks formed from them are igneous rocks that have large crystals because of the slow cooling off of the magma.