Answer:
<h3>The answer is 32 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 768 g
volume = 24 cm³
We have
We have the final answer as
<h3>32 g/cm³</h3>
Hope this helps you
Answer:
carbon and silicon
Explanation:
Various groups of elements in the periodic table have different outermost shell electron configurations. Actually, elements are classified into groups on the basis of the number of electrons on the outermost shell of those elements. All elements with the same number of electrons on their outermost shell belong to the same group in the periodic table.
For elements in group 14, they all have four electrons on their outermost shell. Their general outer electron configuration is ns2 np2 as shown in the question. Two prominent members of this group are carbon and silicon. This ns2 np2 is the ground state outer electron configuration of all group 14 elements in the periodic table.
Ionic bonding would be the answer because they transfer electrons. This gives them a charge. If it loses electrons, it becomes an cation, with a positive charge. While if they gain an electron, they get a negative charge, and become a anion. Transferring an electron is losing or gaining, therefore your answer would be that since electrons are permanently being transferred, the answer is IONIC BOND.
Covalent bonds is a wrong answer because they share electrons, which gives them no charge (neutral).
Also, metallic bonding is not the correct answer.
So our final answer: A- Ionic bond
Answer:
Approximately 75%.
Explanation:
Look up the relative atomic mass of Ca on a modern periodic table:
There are one mole of Ca atoms in each mole of CaCO₃ formula unit.
- The mass of one mole of CaCO₃ is the same as the molar mass of this compound: .
- The mass of one mole of Ca atoms is (numerically) the same as the relative atomic mass of this element: .
Calculate the mass ratio of Ca in a pure sample of CaCO₃:
.
Let the mass of the sample be 100 g. This sample of CaCO₃ contains 30% Ca by mass. In that 100 grams of this sample, there would be of Ca atoms. Assuming that the impurity does not contain any Ca. In other words, all these Ca atoms belong to CaCO₃. Apply the ratio :
.
In other words, by these assumptions, 100 grams of this sample would contain 75 grams of CaCO₃. The percentage mass of CaCO₃ in this sample would thus be equal to:
.
Answer:
Air is a collection of different gases. Mainly nitrogen, and then oxygen. Gas is loosely bound atoms of an element or collection of such in compounds above the temperature required to make them liquid, and colder to make them solid.
Explanation:
hmu if you anything els!