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skad [1K]
3 years ago
5

What two measurements are necessary for calculating velocity?

Physics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

Speed and velocity are both measured using the same units.

Explanation:Speed and velocity are both measured using the same units. The SI unit of distance and displacement is the meter. The SI unit of time is the second. The SI unit of speed and velocity is the ratio of two — the meter per second .

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In an X-ray photoelectron experiment, a photon of wavelength 121 pm ejects an electron from the inner shell of an atom and it em
pentagon [3]

Answer:

binding energy will be 0.1633\times 10^{-15}J

Explanation:

We have given wavelength of photon \lambda =121pm=121\times 10^{-12}m

Velocity of light c=3\times 10^8m/sec

Plank's constant h=6.6\times 10^{-34}Js

So energy of photon E=\frac{hc}{\lambda }=\frac{6.6\times 10^{-34}\times 3\times 10^8}{121\times 10^{-12}}=1.636\times 10^{-15}J

Mass of electron m=9.1\times 10^{-31}kg

Velocity of electron is given v=56.9\times 10^6m/sec

So kinetic energy of electron KE=\frac{1}{2}mv^2=\frac{1}{2}\times 9.1\times 10^{-31}\times (56.9\times 10^6)^2=1.473\times 10^{-15}J

So binding energy = plank's energy - kinetic energy

=1.636\times 10^{-15}-1.473\times 10^{-15}=0.1633\times 10^{-15}J

So binding energy will be 0.1633\times 10^{-15}J

4 0
4 years ago
The current in some DC circuits decays according to the function I=I0e−t/τ, where I is the current at some point in time, I0 is
almond37 [142]

Answer: 1.95

Explanation:

You should start off from the decay formula and solve for τ:

I = I_{0}e^{\frac{t}{\tau\\  } }

\frac{I}{I_{0}} = e^{\frac{-t}{\tau} }

Apply inverse logarithmic function:

ln(\frac{0.2 A}{1.2 A} ) = \frac{-t}{\tau}

The final form will be:

\tau=\frac{-3.5s}{ln(\frac{0.2A}{1.2A} )}

Inputing values for I, IO, and t:

\tau=\frac{-3.5S}{ln(\frac{0.2 A}{1.2 A} )} = 1.95

3 0
4 years ago
Select the correct answer
stepladder [879]
The answer is balloon c is either positively negative or not
8 0
3 years ago
A mechanic jacks up the front of a car to an angle of 8.0° with the horizontal in order to change the front tires. the car is 3.
Zina [86]
<span>First draw a free-body diagram. Torque T = Force F x Distance d where force is the component of gravitational force g and d is the lever arm distance to the pivot point. Since the pivot point is at the back tire we subtract that from the length of the car resulting in d = 1.12 - 0.40 = 0.72 meters = d. We are interested in the perpendicular component of the force exerted on the car jack so use sin 8 degrees then T=1130 kg x 9.81 m/s^2 x sin(8 degrees) x0.72 m = 1,110.80 Newton-meters</span>
5 0
4 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 600 N. Find its shear deformation, taking it to have a
Verizon [17]

Answer:

The shear deformation is \Delta x=3.34\times10^{-6}\ m.

Explanation:

Given that,

Shearing force F = 600 N

Shear modulus S = 1\times10^{9}\ N/m^2

length = 0.700 cm

diameter = 4.00 cm

We need to find the shear deformation

Using formula of shear modulus

S=\dfrac{Fl_{0}}{A\Delta x}

\Delta x=\dfrac{Fl_{0}}{(\dfrac{\pi d^2}{4})S}

\Delta x=\dfrac{4Fl_{0}}{\pi d^2 S}

Put the value into the formula

\Delta x=\dfrac{4\times600\times0.700\times10^{-2}}{3.14\times1\times10^{9}\times(4.00\times10^{-2})^2}

\Delta x=3.34\times10^{-6}\ m

Hence, The shear deformation is \Delta x=3.34\times10^{-6}\ m.

7 0
3 years ago
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