All categories

3 years ago

Signment

Physics

1 answer:

jeka943 years ago

3 0

Answer:

v = 5.15 m/s

Explanation:

At constant velocity, the cable tension will equal the car weight of 984(9.81) = 9,653 N

As the cable tension is less than this value, the car must be accelerating downward.

7730 = 984(9.81 - a)

a = 1.95 m/s²

kinematic equations s = ut + ½at² and v = u + at

-5.00 = u(4.00) + ½(-1.95)4.00²

u = 2.65 m/s the car's initial velocity was upward at 2.65 m/s

v = 2.65 + (-1.95)(4.00)

v = -5.15 m/s

You might be interested in

A jar is completely filled with water, and then it is sealed with a lid. If you push down on the lid with a pressure of 1000 Pa,

notsponge [240]

Answer:

The water pressure at the bottom of the jar will increase by 1000 Pa.

Explanation:

The Pascal principle states that:

In a fluid, a change in pressure at any point in the fluid is transmitted equally throughout the fluid, as it is occuring everywhere.

If we apply this principle at the case mentioned in the problem, we can say that:

- An initial pressure of 1000 Pa is applied on the top of the fluid (the water)

- According to Pascal's law, this pressure is transmitted with equal intensity (1000 Pa) to every point of the fluid

- So, the water pressure at the bottom of the jar will also increase by the same amount, 1000 Pa

5 0

3 years ago

1. The slope of a velocity-time graph is __________

Naddik [55]

Answer:

d. Displacement

Explanation:

3 0

3 years ago

Read 2 more answers

Consider a thin rod of mass 3.2 kg, length 1.2 m and uniform density. The rod is pivoted at one end on a frictionless horizontal

notsponge [240]

Answer:

the angular acceleration is 9.7 rad/ $s^{2}$

Explanation:

given information:

mass of thin rod, m = 3.2 kg

the length of the rod, L = 1.2

angle, θ = 38

to find the acceleration of the rod, we can use the torque's formula as below,

τ = Iα

where

τ = torque

I = inertia

σ = acceleration

moment inertia of this rod, I

I = $\frac{1}{3} mL^{2}$

τ = F d, d = $\frac{L}{2}$ cosθ

τ = m g $\frac{L}{2}$ cosθ

now we can substitute the both equation,

τ = Iα

α = τ/I

= (m g $\frac{L}{2}$ cosθ)/( $\frac{1}{3} mL^{2}$ )

= 3gcosθ/2L

= 3 (9.8)cos 38°/(2 x 1.2)

= 9.7 rad/ $s^{2}$

3 0

3 years ago

Help! Help!

andreyandreev [35.5K]

Answer

I feel the answer is C because it could cause mental and physical trauma

Explanation:

4 0

3 years ago

Two identical charges,2.0m apart,exert forces of magnitude 4.0 N on each other.What is the value of either charge?

storchak [24]

Answer:

$\large \boxed{42\, \mu \text{C}}$$

Explanation:

The formula for the force exerted between two charges is

$F=k \dfrac{ q_1q_2}{r^2}$

where k is the Coulomb constant.

The charges are identical, so we can write the formula as

$F=k\dfrac{q^{2}}{r^2}$

$\begin{array}{rcl}\text{4.0 N}& = & 8.988 \times 10^{9}\text{ N$\cdot$m$^{2}$C$^{-2}$} \times \dfrac{q^{2}}{\text{(2.0 m)}^{2}}\\\\4.0 & = & 2.25 \times 10^{9}\text{ C$^{-2}$} \times q^{2}\\\\q^{2} & = & \dfrac{4.0}{2.25 \times 10^{9}\text{ C$^{-2}$}}\\\\& = & 1.78 \times 10^{-9} \text{ C}^{2}\\q & = & 4.2 \times 10^{-5} \text{ C}\\& = & 42\, \mu \text{C}\\\end{array}\\\text{Each charge has a value of $\large \boxed{\mathbf{42\, \mu }\textbf{C}}$}$

7 0

3 years ago