Using
V = Amplitude x angular frequency(omega)
But omega= 2πf
= 2πx875
=5498.5rad/s
So v= 1.25mm x 5498.5
= 6.82m/s
B. .Acceleration is omega² x radius= 104ms²
actually the answer is B because Chlorine, sulfur, and silicon. Chlorine is a halogen and gas. Sulfur forms an ion with a -2 charge in ionic bonds. Silicon is a well-known metalloid.
Answer
Inertia is the resistance of any physical object to any change in its velocity. This includes changes to the object's speed, or direction of motion. An aspect of this property is the tendency of objects to keep moving in a straight line at a constant speed, when no forces act upon them.
I think the answer to this is centripetal force.
I may not be correct.
Answer:
- The magnitude of the resulting force is 67 lbf.
Explanation:
Taking the east as the positive x direction, and the north as the positive y direction.
The first force points west, this is, in the direction of
, so, is


For the second force, knowing the magnitude and directions relative to the x axis, we can find Cartesian representation of the vectors using the formula

where
is the magnitude of the vector and θ the angle with the positive x direction.
So, the second force is


The net force will be :




To obtain the magnitude, we can use the Pythagorean Theorem



And this is the magnitude we are looking for.