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marusya05 [52]
3 years ago
15

Which is happening when humans control the breeding of living things to favor certain desired features?

Physics
1 answer:
77julia77 [94]3 years ago
5 0
Selective breeding. That is, breeding which uses extreme selectivity
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Acceleration is the magnitude of average velocity true or false
Talja [164]

Answer:

False

Explanation:

8 0
3 years ago
A satellite in a circular orbit of radius R around planet X has an orbital period T. If Planet X had one-fourth as much mass, th
Iteru [2.4K]
<h2>Answer: 2T</h2>

According to the Third Kepler’s Law of Planetary motion <em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.</em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size R of its orbit.

This Law is originally expressed as follows (in the case of planet X and assuming we have a circular orbit):

T^{2}=\frac{4\pi^{2}}{GM}R^{3}    (1)

Where:

G is the Gravitational Constant

M=1.9(10)^{27}kg is the mass of planet X

R  is the radius of the orbit of the satellite around planet X

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=2\pi\sqrt{\frac{R^{3}}{GM}}   (2)

Now, we are asked to find the period when tha mass of the planet is \frac{1}{4}M. In order to do this, we have to rewrite equation (2) with this new value:

T=2\pi\sqrt{\frac{R^{3}}{G(\frac{1}{4}M)}}  (3)

Solving:

T=4\pi\sqrt{\frac{R^{3}}{G(\frac{1}{4}M)}}   (4)

On the other hand, if we multiply both sides of equation (2) by 2, we have:

2T=4\pi\sqrt{\frac{R^{3}}{GM}}    (5)

As we can see, (5) is equal to (4). This means the orbital period is twice the orignal period.

Hence, the answer is:

If Planet X had <u>one-fourth </u>as much mass, the <u>orbital period</u> of this satellite in an orbit of the same radius would be <u>2T.</u>

3 0
3 years ago
Why do streets and highways have speed limits rather than velocity limits?
andrew11 [14]

They actually DO have velocity limits. There are legal restrictions on both speed and direction.

-- Speeds are limited according to the black numbers on white signs that you see on sign-posts everywhere.

-- Directions are limited by the layout of the pavement and curbs on all the highways, avenues, roads, boulevards and streets, as well as the countless signs that say "One Way", "No Left Turn", "Keep Right", "Keep Left", etc. Violate one of these, and you get nailed as sure as if you had exceeded a posted speed limit.

8 0
3 years ago
Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley
kenny6666 [7]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = \frac{g}{7}

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = \frac{4m}{2} x^2  + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2

T = 4mx^2 + 2my^2 -2mxy  

also the general potential energy can be expressed as

U = -4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant

The Lagrangian of the problem can now be setup as

L =4mx^2 +2my^2 -2mxy +2mgy + constant

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange  equation = 4x-y =0\\-2y+x +g = 0

solving the equations simultaneously

x ( acceleration of mass 4m ) = \frac{g}{7}

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

8 0
3 years ago
Which phase of matter contains particles that split into ions and electrons?
Lemur [1.5K]

Answer:

Plasma

Explanation:

7 0
3 years ago
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