Question

How many grams of water are produced when 35.8 grams of Calcium hydroxide reacts with lots of Hydrochloric acid?

Answer 1

Are produced 72 grams of water in this reaction.

Mole calculation

To find the value of moles of a product from the number of moles of a reactant, it is necessary to observe the stoichiometric ratio between them:

                          $Ca(OH)_2 + 2HCl = > 2H_2O + CaCl_2$

Analyzing the reaction, it is possible to see that the stoichiometric ratio is 1:2, so we can perform the following expression:

$MM_{Ca(OH)_2} = 74.1g/mol$

                                           $MM = \frac{g}{mol}$

                                             $74.1 = \frac{35.8}{mol}\\mol = 2$

So, if there are 2 mols of Ca(OH)2:

                                  Ca(OH)2    |    H2O

                                          $\frac{1mol}{2mol} =\frac{2mol}{xmol}$

                                             $x = 4mol$

Finally, just find the number of grams of water using your molar mass:

$MM_{H_2O} = 18g/mol$

                                              $18= \frac{m}{4}\\m = 72g$

So, 72 grams are produced of water in this reaction.

Learn more about mole calculation in: brainly.com/question/2845237