2)

Coal gasification is a multistep process to convert coal into cleaner-burning fuels. In one step, a coal sample reacts with supe

ddd [48]

Answer :

The enthalpy of reaction is, -187.6 kJ/mol

The total heat will be, -2251 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(a) The formation of $CH_4$ will be,

$2C(coal)+2H_2O(g)\rightarrow CH_4(g)+CO_2(g)$ $\Delta H_{rxn}=?$

The intermediate balanced chemical reaction will be,

(1) $C(coal)+H_2O(g)\rightarrow CO(g)+H_2(g)$ $\Delta H_1=29.7kJ$

(2) $CO(g)+H_2O(g)\rightarrow CO_2(g)+H_2(g)$ $\Delta H_2=-41kJ$

(3) $CO(g)+3H_2(g)\rightarrow CH_4(g)+H_2O(g)$ $\Delta H_3=-206kJ$

We are multiplying equation 1 by 2 and then adding all the equations, we get :

(b) The expression for enthalpy of reaction will be,

$\Delta H_{rxn}=2\times \Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H_{rxn}=(2\times 29.7)+(-41)+(-206)$

$\Delta H_{rxn}=-187.6kJ/mol$

Therefore, the enthalpy of reaction is, -187.6 kJ/mol

(c) Now we have to calculate the total heat.

$\Delta H=\frac{q}{n}$

or,

$q=\Delta H\times n$

where,

$\Delta H$ = enthalpy change = -187.6 kJ/mol

q = heat = ?

n = number of moles of coal = $\frac{1.00\times 1000g}{12.00g/mol}=83.33mol$

Now put all the given values in the above formula, we get:

$q=(-187.6kJ/mol)\times (83.33mol)=-2.251kJ$

Thus, the total heat will be, -2251 kJ

4 0

4 years ago

In the balanced equation , CS2 + 3O2 = CO2 + 2SO2 , how many mol of O2 would react with 34.5 mol of CO2?

Arada [10]

Given:

Moles of CS2 (it cannot be CO2 as mentioned in the question, since O2 reacts with CS2 and not CO2) = 34.5 mol

To determine:

Moles of O2 undergoing the reaction

Explanation:

The reaction is-

CS2 + 3O2 → CO2 + 2SO2

Based on the stoichiometry: 3 moles of O2 reacts with 1 mole of CS2

therefore the moles of O2 that would combine with 34.5 moles of CS2 are

= 3 moles O2 * 34.5 moles CS2/1 mole CS2 = 103.5 moles

Ans: Around 104 moles of O2 would react with 34.5 moles of CS2

8 0

3 years ago

Read 2 more answers

Type the appositive phrase in this sentence. "cookies with chocolate chunks," the winning recipe, received $100.

Ymorist [56]

Answer is: the winning recipe.
An appositive is a noun or noun phrase that renames another noun right beside it. The appositive can be a short or long combination of words.
Another example: Problem number 19, the final question, was difficult - the final question is the appositive phrase in this sentence.

5 0

4 years ago

CARDS

valina [46]

Answer:d

Explanation:

8 0

3 years ago

Which of the following do/does not change with the change in temperature?

Phantasy [73]

Answer:

c. Both i & ii

Explanation:

Moles do not change with temperature hence Mole fraction does not depends of temperature.

Molality is number of moles of solutes per kilogram of solvent. It has no relationship with temperature.

This means both of them do not change wit the change in temperature.

Correct option;

c. Both i & ii

8 0

3 years ago