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Dahasolnce [82]
3 years ago
9

Which element consists of positive ions immersed in a "sea" of mobile electronsa) sulfur

Chemistry
1 answer:
Margarita [4]3 years ago
5 0
Hello
Sulfur is the answer
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Select the correct term to complete each sentence.
leva [86]

Answer: 1. halve

2. halve

3. double

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=\frac{hc}{\lambda}

E= energy

\lambda = wavelength of the wave

h = Planck's constant  

c = speed of light

Thus as wavelength and energy have inverse realation, when wavelength will halve , energy will double.

2. The between wavenumber and energy of the wave follows the equation:

E=h\times c\times \bar{\nu}

E= energy

\bar{\nu}\nubar = wavenumber of the wave

h = Planck's constant  

c = speed of light

Thus as wavenumber and energy have direct relation, when wavenumber will halve , energy will be halved.

3. The relationship between energy and frequency of the wave follows the equation:

E=h\times \nu

where

E = energy

h = Planck's constant  

\nu = frequency of the wave

Thus as frequency and energy have direct realation, when frequency will double , energy will double.

3 0
3 years ago
What products would form if chlorine gas was bubbled through a solution of sodium bromide?
Misha Larkins [42]
NaCl would form because it’s a single replacement reaction
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On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of
Murrr4er [49]

Answer:

The empirical formula of the organic compound is  = C_2H_6S_1

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of CO_2 gas at STP occupying 2.0 L = n

n\times 22.4L=2.0L

n=\frac{2.0 L}{22.4 L}=0.08929 mol

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of H_2O gas at STP occupying 3.0 L = n'

n'\times 22.4L=3.0L

n'=\frac{3.0 L}{22.4 L}=0.1339 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of SO_2 gas at STP occupying 1.0 L = n''

n''\times 22.4L=1.0L

n''=\frac{1.0 L}{22.4 L}=0.04464 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = \frac{0.08920 mol}{0.04464 mol}=2

Hydrogen =  \frac{0.2678 mol}{0.04464 mol}=6

Sulfur = \frac{0.04464 mol}{0.04464 mol}=1

The empirical formula of the organic compound is  = C_2H_6S_1

3 0
3 years ago
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