Answer: 1175 J
Explanation:
Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."
Given
Spring constant, k = 102 N/m
Extension of the hose, x = 4.8 m
from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m
Work done =
W = 1/2 k [x(i)² - x(f)²]
Since x(f) = 0, then
W = 1/2 k x(i)²
W = 1/2 * 102 * 4.8²
W = 1/2 * 102 * 23.04
W = 1/2 * 2350.08
W = 1175.04
W = 1175 J
Therefore, the hose does a work of exactly 1175 J on the balloon
THE DOPPLER EFFECT. Anyways, it would have a higher whistle as it approaches you, when it gets to you it only gets quieter because it leaves after. Think of a motorcycle going by, its loud coming to you then as it passes it gets quieter.
Answer:
0.137m²
Explanation:
Pressure = Force/Area
Given
Force = 41,500N
Pressure = 3.00atm
since 1atm = 101325.00 N/m²
3atm = 3(101325.00)
3atm = 303,975N/m²
Pressure = 303,975N/m²
Get the area
Area = Force/Pressure
Area = 41500/303,975
Area = 0.137m²'
Hence the surface area of the inside of the tire is 0.137m²
Only if a force acts upon it, it can move.
