Answer: r^-1
Explanation:
V = (k × Q) / r, where V is electric potential, k is constant and r is distance from charge.
Since Q will not change, it can be considered a constant too.
So, we can write V ∝ 1/r
which is same as V ∝ r^-1
Answer:
Image
Explanation:
I looked at the graph and assumed answers
A point at which parts of an artificial structure are joined. Hope this helps
Answer:
Let the mass of the book be "m", acceleration due to gravity be "g", velocity be "v" and height be "h".
Now if we are holding a book at a certain height (h), <em><u>the potential energy will be maximum which is equal to mass× acceleration due to gravity× height (= mgh)</u>.</em>
(Remember: kinetic energy =0)
Now we consider that the book is dropped, in this case a force will act downward towards the centre of the earth, <em><u>Force= mass× acceleration due to gravity (F=mg)</u></em>. It is equal to the weight of the book.
While the book is falling, the potential energy stored in the book converts into kinetic energy and strikes the floor with <em><u>the maximum kinetic energy= (1/2)×mass×velocity² (=1/2mv²)</u>.</em>
(Remember: kinetic energy=0)
Due to this process the whole energy is conserved.
As the potential energy decreases kinetic energy increases.
It shortens so that the tips reach faster