Answer:
The percentage yield of LiOH is 39.9%
Explanation:
From the question given above, the following data were obtained:
Theoretical yield = 47.4 g
Actual yield = 18.9 g
Percentage yield =?
The percentage yield of LiOH can be obtained as follow:
Percentage yield = Actual yield / Theoretical yield × 100
Percentage yield = 18.9 / 47.4 × 100
Percentage yield = 1890 / 47.4
Percentage yield = 39.9%
Therefore, percentage yield of LiOH is 39.9%
Answer:
The correct answer is - 10400 years.
Explanation:
Half-life an element is the time required to decay the half amount of the initial amount of the element.
Here, the initial amount n(i) = 100 gm
remained amount n(r) = 25 gm
then n =?
The formula for the calculating initial amount
n(i)=n(r)⋅2^n
n(i)=n(r)⋅2^n
n(i)/n(r) =2^n
puting value,
100/25 = 2^n
2^n = 4
n = 2
so to decay this amount there is two half life cycles involved,
Thus, time = 2*5700
= 10400 years.
Answer:
I don't know what the correct answer is
Explanation:
Answer:
83.99 KC1 1.
Explanation:
What is the total number of grams of KCl (formula 2.200M=xmol - 200 mdr o mass = 74.6) in 1.00 liter of 0.200 molar solution? 3941+355 74.69 ml atonal 1.13 mol 174.6g) = 83.99 KC1 1.