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Vlad [161]
3 years ago
14

Suppose an acorn with a mass of 3.17 g falls off a tree. At a particular moment during the fall, the acorn has a kinetic energy

of 0.299 J and a potential energy of 0.167 J with respect to the ground.
How does the acorn's potential and kinetic energy change as it falls?

a. Both potential and kinetic energy decrease.

b. Polential encrgy increases and kinetic energy decreases.

c. Potential energy decreases and kinetic energy increases.

d. Both potential and kinetic energy increase.
Chemistry
1 answer:
Alona [7]3 years ago
4 0

Answer:

Option A is correct

Explanation:

Potential energy of acorn is due to its position i.e height and kinetic energy Is due to velocity or speed with which it is moving. When the acorn is at tree, its potential energy is maximum and kinetic energy is zero. While it starts moving downward, the height starts reducing and the speed increase. Thus potential energy reduces and kinetic energy increases.  

But as it touches the ground, its kinetic energy becomes zero as speed is zero and potential energy also becomes zero as height is zero.  

Thus, option A is correct

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When hydrochloric acid is poured over potassium sulfide, 42.5 mL of hydrogen sulfide gas is produced at a pressure of 756 torr a
EastWind [94]
<h2>Answer:</h2>0.1899grams

<h2>Explanations:</h2>

The balanced chemical reaction between hydrochloric acid and potassium sulfide is as shown:

K_2S+2HCl\to H_2S+2KCl

Based on stoichiometry, we can see that 1 mole of potassium sulfide reacted to form 1 mole of hydrogen sulfide.

Get the mole of hydrogen sulfide gas (H2S) using the ideal gas equation expressed as:

\begin{gathered} PV=\text{nRT} \\ n=\frac{PV}{RT} \end{gathered}

P is the pressure of the gas (in atm) = 0.994737atm (756torr)

V is the volume of the gas = 42.5mL = 0.0425L

T is the temperature (in Kelvin) = 26 + 273 = 299K

R is the gas constant = 0.0821 L*atm/mole * K

Substitute these values into the formula as shown:

\begin{gathered} n=\frac{0.994737\cancel{\text{atm}}\times0.0425\cancel{L}}{0.0821\frac{\cancel{L}\cdot\cancel{\text{atm}}}{\text{mole}\cdot\cancel{K}}\times299\cancel{K}} \\ n=\frac{0.994737\times0.0425}{0.0821\times299} \\ n=\frac{0.0422763225}{24.5479} \\ n=0.00172\text{moles} \end{gathered}

Since the number of moles of hydrogen sulfide is 0.00172moles, the number of moles of potassium sulfide will also be 0.00172 moles (based on stoichiometry)

Get the mass of potassium sulfide that reacted using the formula:

\text{Mass}=number\text{ of moles}\times molar\text{ mass}

Number of moles of K2S = 0.00172 moles

Molar mass of K2S = 110.262 g/mol

Substitute into the formula for calculating the mass;

\begin{gathered} \text{Mass}=0.00172\cancel{\text{moles}}\times\frac{110.262g}{\cancel{\text{mole}}} \\ \text{Mass}=0.1899\text{grams} \end{gathered}

Therefore the mass of potassium sulfide that reacted (in grams) is approximately 0.1899grams

3 0
1 year ago
LeAnn knows the speed of an airplane but she wants to find the velocity. What does she need to determine to find velocity?
SCORPION-xisa [38]
A.
The time it takes the airplane to move between two points
6 0
3 years ago
Why we use cotton cloth to mop the floor?
ch4aika [34]

Answer:

because cotton have a good absorbing quality and can absorb water more which is used to mop the floor

Explanation:

4 0
2 years ago
A gas occupies 3.56 L at 1.00 atm. What will be the volume of this gas if the pressure becomes 4.00 atm?
coldgirl [10]

Answer:

0.890 L

Explanation:

P1V1 = P2V2

P1 = 1.00 atm

V1 = 3.56 L

P2 = 4.00 atm

V2 = ?

Solve for V2 --> V2 = P1V1/P2

V2 = (1.00 atm)(3.56 L) / (4.00 atm) = 0.890 L

8 0
3 years ago
Mandelic Acid is an organic acid composed of carbon (63.15%), hydrogen (5.30%), and oxygen (31.55%). Its molar mass is 152.14 g/
Dafna1 [17]

Answer:

Empirical formula is C3H3O

Molecular formula C9H9O3

Explanation:

From the question given, we obtained the following data:

Carbon = 63.15%

Hydrogen = 5.30%

Oxygen = 31.55%

We can obtain the empirical and molecular formula by doing the following as illustrated in the attached file. Please see attachment for explanation.

3 0
4 years ago
Read 2 more answers
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