Answer:
a) 26.98
b) 3
c) 3* 1.01 = 3.03
d) 3 *16 = 48
e) 26.98 + 3.03 + 48 = 78.01
f) 6.023 * 10²³
H2SO4 ---> 2H^+ + SO4^2-
Hence n H+ = 9 mols
Mass of H = nM = (9*1) = 9g
Alternately
mass of H2SO4= nM= 4.5*98= 441
Mass of H= mass h2so4 * molar mass of H/molar mass of h2so4
Mass of H= 441 * 2/98 = 9g
3 Chlorine ions are required to bond with one aluminum ion.
In ionic bonds, metals atoms loses all its outermost shell electrons to form a cation. While, non metal atoms gains however many electrons in order to make its outermost electron shell be 8 (or 2 if there's only one shell).
Therefore, form the periodic table, we can see that aluminum has a atomic number of 13, which makes its electron arrangement be 2,8,3. So, in order to form a aluminum ion, an Al atom must lose 3 electrons. On the other hand, Chlorine has a atomic number of 17, which means it has the electron configuration of 2,8,7. It has to gain only 1 electron to have 8 outermost shell electron.
Thereofre, 3 Chlorine atom are required to gain all 3 electrons given out by just 1 aluminum ion.
Answer:
They are solid (with the exception of mercury, Hg, a liquid).
They are shiny, good conductors of electricity and heat.
They are ductile (they can be drawn into thin wires).
They are malleable (they can be easily hammered into very thin sheets).
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The balanced reaction is:<span>
MnO2(s) + 4HCl(aq) → Cl2(g) + MnCl2(aq) + 2H2O(l)
We
are given the amount of hydrochloric acid to be used for the reaction. This
will be the starting point for the calculations.
1.82 mol
HCl ( 1 mol Cl2 / 4 mol HCl) = 0.46 mol Cl2
<span>Therefore,
0.46 mol of chlorine gas is produced for the reaction of hydrochloric acid and
manganese oxide.</span></span>
