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ikadub [295]
3 years ago
5

If air resistance in neglected, show (algebraically) that a ball thrown vertically upwards with a speed of Vo will have the same

speed, Vo, when it comes back down to starting point.
Physics
2 answers:
VARVARA [1.3K]3 years ago
6 0

Explanation:

If the air resistance is negligible then in that case we can say that there will be only one force on the ball

Force of gravity

so here we will have

F_g = mg

so the acceleration of the ball is given as

a = g

now we have

v_f^2 - v_i^2 = 2a s

as the ball returns to initial position

so the displacement must be zero

v_f^2 - v_i^2 = 0

so here we have

v_f = vi

Bond [772]3 years ago
4 0
Velocity =   displacement/time ; In variable form, we can say
 Vo = d/t ....(1)
Using the kinematic equationd =  t*(Vo + Vf)/2 ...(2)
Where Vf is the final velocity, but in this scenario,  we are saying it is the same as the initial velocity hence, (2) becomes

d = t*(Vo + Vo)/2
d = t*(2*Vo)/2
the 2's cancel
d = t*Vo
solving for Vo we get,
Vo = d/t which is the exact same as 1. Keep in mind the distance traveled does not change
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Air is cooled in a process with constant pressure of 150 kPa. Before the process begins, air has a specific volume of 0.062 m^3/
Mama L [17]

Answer:

The pressure is constant, and it is P = 150kpa.

the specific volumes are:

initial = 0.062 m^3/kg

final = 0.027 m^3/kg.

Then, the specific work can be written as:

W = \int\limits^{vf}_{vi} {Pdv} \, = P(vf - vi) = 150kPa*(0.0027 - 0.062)m^3/kg = -5.25 kPa*m^3/kg.

The fact that the work is negative, means that we need to apply work to the air in order to compress it.

Now, to write it in more common units we have that:

1 kPa*m^3 = 1000J.

-5.25 kPa*m^3/kg = -5250 J/kg.

7 0
3 years ago
A car mass of 1.2 x 10 kilograms starts from rest and attains a speed of 20 meters/seconds in 5 seconds. What net force acted on
lorasvet [3.4K]

Net force on the car=F=4.8 x 10³ N

Explanation:

mass of car= 1.2 x 10³ Kg

initial velocity= Vi=0

Final velocity= Vf= 20 m/s

time = t= 5 s

Using kinematic equation,

Vf= Vi + at

20= 0 + a (5)

5 a=20

a= 20/5

a= 4 m/s²

Now force is given by F = ma

F= 1.2 x 10³ (4)

F=4.8 x 10³ N

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The formula is=1/2(m x v^2)

so = 1/2*(0.05)*(310)^2

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yaroslaw [1]

Answer:

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Explanation:

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