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3 years ago

What is the function of the commutator in a motor?

2 answers:

7 0

The answer you are looking for is:
D.) It facilitates the moment of the current though a wire.
Hope that helps!!
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RSB [31]3 years ago

7 0

Answer:

Explanation:

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A technician wearing a brass bracelet enclosing area 0.00500 m2 places her hand in a solenoid whose magnetic field is 4.50 T dir

notka56 [123]

Answer:

39.375 A

Explanation:

To find the induced current, we use the relation

e = -ΔΦ/Δt, where

ΔΦ = change in magnetic flux of the bracelet

Δt = change in time, = 20 ms

Also, Φ = A.ΔB, such that

A = area of the bracelet, 0.005m²

ΔB = magnetic field strength of the bracelet = 1.35 - 4.5 = -3.15 T

ΔΦ = A.ΔB

ΔΦ = 0.005 * -3.15

ΔΦ = -.01575 wb

e = -ΔΦ/Δt

e = -0.01575 / 20*10^-3

e = 0.7875 V

From the question, the resistance of the bracelet is 0.02 ohm, so

From Ohms Law, I = V/R

I = 0.7875 / 0.02

I = 39.375 A

6 0

3 years ago

A pitcher throws a 0.144-kg baseball toward the batter so that it crosses home plate horizontally and has a speed of 42 m/s just

Solnce55 [7]

(a) 12.8 kg m/s

The impulse delivered by the bat on the baseball is equal to the change in momentum of the baseball:

$I=\Delta p = m(v-u)$

where we have

m = 0.144 kg is the mass of the ball

v = -47 m/s is the final velocity of the ball

u = 42 m/s is the initial velocity of the ball

Substituting into the equation, we find

$I=(0.144 kg)(-47 m/s-(42 m/s))=-12.8 kg m/s$

And since we are interested in the magnitude only,

$I=12.8 kg m/s$

(b) 2.78 kN

The impulse exerted on the ball is also equal to the product between the average force and the contact time:

$I=F\Delta t$

where

F is the average force exerted on the ball

$\Delta t=0.0046 s$ is the contact time

Solving the formula for F, we find

$F=\frac{I}{\Delta t}=\frac{12.8 kg m/s}{0.0046 s}=2783 N = 2.78 kN$

(c) The force exerted on the ball is much larger (1988 times more) than the weigth of the ball

The weight of the ball is given by

$W=mg$

where

m = 0.144 kg is the mass of the ball

g = 9.8 m/s^2 is the acceleration due to gravity

Solving the equation for W, we find

$W=(0.144 kg)(9.8 m/s^2)=1.4 N$

So as we see, the force exerted on the ball (2783 N) is almost 2000 times larger than the weight of the ball (1.4 N):

$\frac{F}{W}=\frac{2783 N}{1.4 N}=1988$

8 0

3 years ago

4. Protons and neutrons are held together to form this _________

Olenka [21]

Answer:

strong nuclear force.

Explanation:

hope this helps you!!

8 0

2 years ago

Millikan measured the electron's charge by observing tiny charged oil drops in an electric field. Each drop had a charge imbalan

IceJOKER [234]

Answer:

$4.8\cdot 10^{-19} C$

Explanation:

For a drop in equilibrium, the weight is equal to the electric force (in magnitude):

$W = F_e$

where here we have

$W=1.00\cdot 10^{-14}N$ is the weight of the drop

$F_e$ is the magnitude of the electric force, which can be rewritten as

$F_e = qE$

where

q is the charge of the oil drop

$E=2.08 \cdot 10^4 N/C$ is the magnitude of the electric field

Substituting into the equation and solving for q, we find the charge of the oil drop:

$q=\frac{W}{F_e}=\frac{1.00\cdot 10^{-14}N}{2.08\cdot 10^4 N/C}=4.8\cdot 10^{-19} C$

7 0

3 years ago

The Pacific Ocean has a durface area of about 116,214,700 km^2 and an average depth of 3940m. Estimate the volume of the Pacific

Anastaziya [24]

The volume is given by:

V = Ad

V = volume, A = surface area, d = depth

Given values:

A = 116214700km² = 1.162147×10¹⁸cm², d = 3940m = 394000cm

Plug in and solve for V:

V = 1.162147×10¹⁸(394000)

V = 4.57885918×10²³cm³

4 0

3 years ago