Question

an object weighting 100g is thrown upwards from the ground at a speed of 100 m/s.where will the potential energy of the object be two thirds of the kinetic energy?

Answer 1

Answer:

333.3 m

Explanation:

Given

$m =100g\ =\ 0.1kg\\v = 100 m/s\\g = 10 m/s ^2$

Potential energy =$\frac{2}{3}\ of\ Kinetic\ energy$......Equation(1)

We know that

Potential energy=mgh

Kinetic energy =$\frac{1}{2} mv^{2}$

Now From the Equation(1)

$mgh=\frac{2}{3}*\frac{1}{2} mv^{2}\\ gh=\frac{v^{2} }{3} \\10 * h=\ \frac{10000}{3}\\ h=\ \frac{1000}{3} \\h=333.3\ m$