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Minchanka [31]
4 years ago
7

You're trying to stop a car that is rolling down-hill. Gravity is pulling it forward with a force of 200 N. If the car has a mas

s of 650 kg, and you want to
it accelerate at -0.15 m/s/s, what force do you need to apply to the car? (Your goal is to find the actual number for the force that you are applying.)
Physics
1 answer:
lara31 [8.8K]4 years ago
8 0

Answer:

no idea .

Explanation:

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A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magni
d1i1m1o1n [39]

Answer:

a) 1.62*10^{-18}N

b) 2.84*10^{-19}N

c) 1.16*10^{-18}N

Explanation:

The net force is given by the expression:

\vec{F}=q(\vec{E}+\vec{v}\ X\ \vec{B})

By the right hand rule, we know that the direction of the magnetic force is

j X -i = k

\vec{v}X\vec{B}=vB\hat{k}

Hence, the direction of the magnetic force is the +z direction.

(a) E=4.19V/m k

F=(1.6*10^{-19}C)[4.19\frac{V}{m}+(2540\frac{m}{s})(2.35*10^{-3}T)]=1.62*10^{-18}N

where we have used q=9.1*10^{-31}kg.

(b) E=-4.19V/m k

F=(1.6*10^{-19}C)[-4.19\frac{V}{m}+(2540\frac{m}{s})(2.35*10^{-3}T)]=2.84*10^{-19}N

(c) E=4.19V/m i

In this case the net force will have two components:

F=(1.6*10^{-19}C)[4.19\frac{V}{m}\hat{i}+(2540\frac{m}{s})(2.35*10^{-3}T)\hat{k}]\\\\F=[6.704*10^{-19}\hat{i}+9.55*10^{-19}\hat{k}]N

and its magnitude will be:

F=\sqrt{(6.704*10^{-19})^2+(9.55*10^{-19})^2}=1.16*10^{-18}N

hope this helps!!

5 0
3 years ago
Why dont we put (-ve) sign when calculating charge in electrostatics ?​
Levart [38]

Answer:

The negative sign represents the flow of charge in an opposite direction relative to point of action.

5 0
3 years ago
physics A river flows at a speed vr = 5.37 km/hr with respect to the shoreline. A boat needs to go perpendicular to the shorelin
vova2212 [387]

Answer: Vb is the vector  (-5.37m/s,  8.59 m/s), with a module 10.13m/s

then the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9

Explanation:

We can use the notation (x, y) where the river flows in the x-axis and the pier is on the y-axis.

We have Vr = (5.37m/s, 0m/s)

Now, if the boat wants to move only along the y-axis (perpendicularly to the shore).

The velocity of the boat Vb will be:

Vb = (-c*sin(32). c*cos(32))

Then we should have that:

5.37 m/s - c*sin(32) = 0

c = (5.37/sin(32))m/s = 10.13 m/s

the velocity in the y-axis is:

10.13m/s*cos(32) = 8.59 m/s

So Vb = (-5.37m/s,  8.59 m/s)

the ratio Vb/Vr = 10.13m/s/5.37m/s = 1.9 where i used Vb as the module of the boat's velocity.

7 0
3 years ago
An object is acted upon by the forces F1equalsleft angle12​,7​,2right angle and F2equalsleft angle0​,4​,8right angle. Find the f
Umnica [9.8K]

Answer:

F_3=(-12,-11,-10)

Explanation:

It is given that,

Force, F_1=(12,7,2)

Force, F_2=(0,4,8)

We need to find the force F₃ that must act on the object so that the sum of the forces is zero. Let F_3=(x,y,z)

According to question, F_1+F_2+F_3=0

(12,7,2)+(0,4,8)+(x,y,z)=0

(12+x)+(11+y)+(10+z)=0

Since, 12 + x = 0, 11 + y = 0 and 10 + z = 0

The third force is equal to,

F_3=(-12,-11,-10)

Hence, this is the required solution.

4 0
3 years ago
7. A 78-kg skydiver has a speed of 62 m/s at an altitude of 870 m above the ground.
miv72 [106K]

The kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

To find the answer, we need to know about the expression of kinetic energy and potential energy.

<h3>What are the expressions of kinetic energy and potential energy?</h3>
  • Mathematically, kinetic energy= 1/2 × mass × velocity²
  • Gravitational potential energy near the earth surface= mass × g × height on the earth surface

<h3>What's the kinetic energy, potential energy and total mechanical energy of the 78kg skydriver at 870 m on earth surface with 62 m/s velocity?</h3>
  • Kinetic energy= 1/2 × 78 × 62² = 1.5 × 10⁵ Joule
  • Potential energy= 78×9.8×870= 6.7× 10⁵ Joule
<h3>What's the total mechanical energy?</h3>
  • Mechanical energy= kinetic energy+ potential energy
  • 1.5 × 10⁵ Joule + 6.7× 10⁵ Joule = 8.2× 10⁵ Joule

Thus, we can conclude that the kinetic energy, potential energy and total mechanical energy possessed by the skydriver are 1.5 × 10⁵ Joule, 6.7 × 10⁵ Joule and 8.2 × 10⁵ Joule respectively.

Learn more about the kinetic energy, potential energy and mechanical energy here:

brainly.com/question/17051553

#SPJ1

8 0
2 years ago
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