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posledela
3 years ago
5

Two point charges carrying charges q1 = +3 μC and q2 = −4 μC are fixed on the x − y plane at positions (x1 = 3.5 cm, y1 = 0.5 cm

) and (x2 = −2 cm, y2 = 1.5 cm) respectively.
a) Find the magnitude and direction of the electrostatic force on charge q2.
b) Where in the x − y plane can you place a third charge q3 = 4 μC, such that the net electrostatic force on charge q2 is zero?

Physics
1 answer:
Stells [14]3 years ago
3 0

Answer:

Explanation:

The concept of coulomb's law was applied to analyze the problem and other mathematical application as is shown in the attached file.

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Answer:

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Explanation:

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3 years ago
A man with a mass of 65.0 kg skis down a frictionless hill that is 5.00 m high. At the bottom of the hill the terrain levels out
anzhelika [568]

Answer:

The horizontal distance is 4.823 m

Solution:

As per the question:

Mass of man, m = 65.0 kg

Height of the hill, H = 5.00 m

Mass of the backpack, m' = 20.0 kg

Height of ledge, h = 2 m

Now,

To calculate the horizontal distance from the edge of the ledge:

Making use of the principle of conservation of energy both at the top and bottom of the hill (frictionless), the total mechanical energy will remain conserved.

Now,

KE_{initial} + PE_{initial} = KE_{final} + PE_{final}

where

KE = Kinetic energy

PE = Potential energy

Initially, the man starts, form rest thus the velocity at start will be zero and hence the initial Kinetic energy will also be zero.

Also, the initial potential energy will be converted into the kinetic energy thus the final potential energy will be zero.

Therefore,

0 + mgH = \frac{1}{2}mv^{2} + 0

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Now,

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Now, time taken for the fall:

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7 0
3 years ago
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Anvisha [2.4K]

Answer:

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Using stored energy in spring

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3 0
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ivanzaharov [21]

Answer:

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2 years ago
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