All categories

2 years ago

A body of mass 11 kg is subjected to a net force of 20 N East for 30 s. Calculate the change in

Physics

1 answer:

Vanyuwa [196]2 years ago

5 0

Answer:

54.55 m/s

Explanation:

From the question above,

Change in velocity = impulse/mass

Δv = I/m = Ft/m................... Equation 1

Where F = force, t = time, m = mass

Given: F = 20 N, t = 30 s, m = 11 kg

Substitute these values into equation 1

Δv = (20×30)/11

Δv = 600/11

Δv = 54.55 m/s

Hence the change in velocity of the body is 54.55 m/s

You might be interested in

The speed of a star, can you measure it? Is it constant?

natka813 [3]

Explanation:

the spped of that we can't measure with own that measure a machine is called

8 0

2 years ago

Oscilloscopes have parallel metal plates inside them to deflect the electron beam. These plates are called the deflecting plates

alexdok [17]

Answer:

1.6 pF

Explanation:

The capacitance of a parallel-plate capacitor in air is given by:

$C=\frac{\epsilon_0 A}{d}$

where

$\epsilon_0$ is the vacuum permittivity

A is the area of each plate

d is the separation between the plates

In this problem we have:

- Separation between the plates: d = 5.00 mm = 0.005 m

- Area of the plates: $A = 3.00 cm \cdot 3.00 cm = 9.00 cm^2 = 9\cdot 10^{-4}m^2$

Therefore, the capacitance is

$C=\frac{(8.85\cdot 10^{-12}F/m)(9\cdot 10^{-4} m^2)}{0.005 m}=1.6\cdot 10^{-12} F=1.6 pF$

8 0

3 years ago

Problem 9.49: Air enters the turbine of a gas turbine at 1200 kPa, 1200 K, and expands to 100 kPa in two stages. Between the sta

Nitella [24]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

8 0

2 years ago

The upward force on an airplane's wing is thrust.

kompoz [17]

No. 'Thrust' is what most people in aviation call the force
that pushes the aircraft forward.

The same people generally call the upward force on the wing "lift".

3 0

3 years ago

To test the performance of its tires, a car

Rom4ik [11]

The coefficient of static friction is 0.222

Explanation:

In order for the car to remain in circular motion, the frictional force must be able to provide the necessary centripetal force. Therefore, the car will start skidding when the two forces are equal:

$\mu mg=m\frac{v^2}{r}$