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valina [46]
3 years ago
6

Ethanol, C2H6O, is most often blended with gasoline - usually as a 10 percent mix - to create a fuel called gasohol. Ethanol is

a renewable resource and ethanol-blended fuels, like gasohol, appear to burn more efficiently in combustion engines. The heat of combustion of ethanol is 326.7 kcal/mol. The heat of combustion of octane, C8H18, is 1.308×103 kcal/mol. How much energy is released during the complete combustion of 406 grams of octane ? kcal Assuming the same efficiency, would 406 grams of ethanol provide more, less, or the same amount of energy as 406 grams of octane?
Chemistry
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Explanation:

Given,

The heat of combustion of octane = 1.308×10³ kcal/mol

It means that combustion of 1 mole of octane produces 1.308×10³ kcal of energy

Given mass = 406 g

Molar mass of octane = 114.23 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{406\ g}{114.23\ g/mol}

Moles of octane = 3.5542 moles

Combustion of 3.5542 moles produces 3.5542×1.308×10³ kcal of energy

<u>Energy released from 406 grams of octane = 4.649×10³ kcal</u>

Also given,

The heat of combustion of ethanol = 326.7 kcal/mol

It means that combustion of 1 mole of octane produces 326.7 kcal of energy

Given mass = 406 g

Molar mass of octane = 46.07 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{406\ g}{46.07\ g/mol}

Moles of octane = 8.8127 moles

Combustion of 8.8127 moles produces 8.8127×326.7 kcal of energy

<u>Energy released from 406 grams of ethanol= 2879.11 kcal = 2.879×10³ kcal</u>

<u>It is less.</u>

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nignag [31]

Answer:

0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂

Explanation:

In first place, the balanced reaction between Mg and O₂ is:

2 Mg + O₂ ⇒ 2 MgO

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:

  • Mg: 2 moles
  • O₂: 1 mole
  • MgO: 2 moles

Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?

moles of MgO=\frac{0.250 moles of Mg*2 moles of MgO}{2 moles of Mg}

moles of MgO= 0.250

<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>

3 0
3 years ago
(b)
mixas84 [53]

Answer:

Group 18th

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The group 18th of periodic table which is composed of Noble gases mainly was missing from the Mendeleev's periodic table. The reason for this is that Noble gases are least reactive, therefore, it was difficult to predict such elements which do not react with other elements.

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An element’s atomic number is the?
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n a gas-phase equilibrium mixture of SbCl5, SbCl3, and Cl2 at 500 K, pSbCl5 = 0.17 bar and pSbCl3 = 0.22 bar. Calculate the equi
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Answer:

2.7 × 10⁻⁴ bar

Explanation:

Let's consider the following reaction at equilibrium.

SbCl₅(g) ⇄ SbCl₃(g) + Cl₂(g)

The pressure equilibrium constant (Kp) is 3.5 × 10⁻⁴. We can use these data and the partial pressures at equilibrium of SbCl₅ and SbCl₃, to find the partial pressure at equilibrium of Cl₂.

Kp = pSbCl₃ × pCl₂ / pSbCl₅

pCl₂ = Kp × pSbCl₅ / pSbCl₃

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pCl₂ = 2.7 × 10⁻⁴ bar

7 0
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