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marysya [2.9K]
3 years ago
13

Calcium hydroxide + hydrochloric acid → calcium chloride + water

Chemistry
2 answers:
Andrew [12]3 years ago
7 0

Answer : The correct balanced chemical reaction will be:

Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(s)+2H_2O(aq)

Explanation :

When calcium hydroxide react with hydrochloric acid then it react to give calcium chloride and water as a product.

This reaction is double-displacement reaction.

Double-displacement reaction : It is defined as the reaction in which the cation of two reactants molecule exchange their places to give two different products.

Thus, the correct balanced chemical reaction will be:

Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(s)+2H_2O(aq)

Lubov Fominskaja [6]3 years ago
5 0

Answer:

D

Explanation: iIt is a neutralization reaction and neutralization reaction is a reaction between and acid and base to give salt and water. In the question above, Ca(OH)2 is the base and HCl is the acid, Ca(Cl)2 is the salt and H2O.

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Converting the following mm Hg (torr) to standard
11Alexandr11 [23.1K]

Explanation:

Given:

20.5 torr

78.6 torr

225 torr

Change into atm

Computation:

We know that;

1 torr = 0.00131579 atm

So,

1. 20.5 torr

= 20.5 x 0.00131579 atm

= 0.02697

= 0.027 atm (Approx)

2. 78.6 torr

= 78.6 x 0.00131579 atm

= 0.103090

= 0.103 atm (Approx)

3. 225 torr

= 225 x 0.00131579 atm

= 0.2960

= 0.296 atm (Approx)

5 0
3 years ago
What would the volume of a gas be at 150c if had of volume of 693 ml at 45 c​
Vlad1618 [11]

Answer:

Explanation:

T1 = 150°C = (150 + 273.15)K = 423.15K

T2 = 45°C = (45 + 273.15)K = 318K

V1 = 693mL = 693cm³

Applying Charle's law, the volume of a given gas is directly proportional to is temperature provided that pressure remains constant.

V = kT

V1 / T1 = V2 / T2

693 / 423.15 = V2 / 318

V2 = (693 * 318) / 423.15 = 520.79cm³

The new volume of the gas is 520.79cm³

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3 0
3 years ago
The pre-exponential constant and activation energy for the diffusion of iron in cobalt are 1.7 x 10-5 m2/s and 273,300 J/mol, re
Kitty [74]

<u>Answer:</u> The temperature of the system will be 1622 K

<u>Explanation:</u>

The equation relating the pre-exponential factor and activation energy follows:

\log D=\log D_o-\frac{E_a}{2.303RT}

where,

D = diffusion coefficient = 2.7\times 10^{-14}m^2/s

D_o = pre-exponential constant = 1.7\times 10^{-5}m^2/s

E_a = activation energy of iron in cobalt = 273,300 J/mol

R = Gas constant = 8.314 J/mol.K

T = temperature = ?

Putting values in above equation, we get:

\log (2.7\times 10^{-14})=\log (1.7\times 10^{-5})-\frac{273,300}{2.303\times 8.314\times T}\\\\T=1622K

Hence, the temperature of the system will be 1622 K

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3 years ago
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