anything except for a and d
A<em>ns</em><em>w</em><em>e</em><em>r</em>
<h2>
<em>K </em><em>eq</em><em>=</em><em>1</em><em>.</em><em>3</em><em>3</em></h2>
<em>please </em><em>see</em><em> the</em><em> attached</em><em> </em><em>picture.</em><em>.</em><em>.</em><em>.</em>
<em>Hope </em><em>it</em><em> helps</em><em>.</em><em>.</em>
<em>good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Based on the observations from, the substance that water is more attracted to are polar substances.
<h3>
What is the Polarity of water?</h3>
Water is a compound made up of 2 atoms of hydrogen and 1 atom of oxygen.
Water molecule is polar due to the unequal sharing of electrons between the atoms and the unsymmetrical shape of the molecule.
Since water molecules are polar, they are more attracted to molecules that are also polar.
Thus, based on the observations from, the substance that water is more attracted to are polar substances.
Learn more about water here: brainly.com/question/5060579
#SPJ1
Answer:
0.42 M
Explanation:
The reaction that takes place is:
- Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)
First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:
(200 mL = 0.200L)
- 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄
Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:
- 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂
Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:
- 0.224 mol - 0.14 mol = 0.085 mol
Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:
- 0.085 mol / 0.200 L = 0.42 M
Answer:
i can't understand your question haha
