Answer:
R = mg
F = µsR
Fs= 0.4 × ( 88 × 10)
Fs = 772 N
Fk= µk R
Fs= 1.33 × 880 N
Net force = (772+(1.33×880))-240 N
For a radio station broadcasts at a frequency of 83.8 MHz with a power of 16.5 kW, the number of photons is mathematically given as
P=6.92*10^{29}photon/sec
<h3>What is the number of photons does the antenna of the station emit in each second?</h3>
Generally, the equation for the energy is mathematically given as
E=hf
Therefore
E=6.63*10^{34}*83*10^6
E=5.561*10^26J
In conclusion, the number of photons
P=dN/dt
P=38500/5.561*10^{26}
P=6.92*10^{29}photon/sec
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brainly.com/question/13439286
Answer:
Ferromagnetism, physical phenomenon in which certain electrically uncharged materials strongly attract others. Two materials found in nature, lodestone (or magnetite, an oxide of iron, Fe3O4) and iron, have the ability to acquire such attractive powers, and they are often called natural ferromagnets.
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They were both odd and obsessive
Answer:
λ = 6 10⁻⁷ m
Explanation:
This problem is a double slit interference spectrum where bright maxima are described by constructive interference.
d sin θ = m λ
Where d is the gap of the slits (d = 0.2 10⁻³ m), m is the maximum interference and λ is the wavelength
We used trigonometry to find the angle
tan θ = y / x
Since the angles in these experiments are very small we use
tan θ = sin θ / cos θ = sin θ
sin θ = y / x
We substitute
d y / x = m λ
λ = d y / m x
In this case the first maximum is m = 1
We substitute
λ = 0.2 10⁻³ 3.6 10⁻³ / (1 1.2)
λ = 6 10⁻⁷ m
The approximation made in this problem is that since the angles are small we approximate the tangent to the sine