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mihalych1998 [28]
2 years ago
9

Hydrazine is a great chemical propellant because it creates a lot of gaseous products that need to expand and escape from their

reaction space. Based on this information, what physical characteristics of a reaction would you look for when trying to find new propellants?
Chemistry
1 answer:
Burka [1]2 years ago
4 0

We have to look for safe and non - hazardous characterstics when trying to find new propellants.

<h3>What are propellants ?</h3>

Propellants are any gas, liquid, or solid the expansion of which can be used to impart motion to another substance or object.

The Desirable properties for propellant combinations are ;

  • low molecular mass and high temperature of reaction products (for high exhaust velocity),
  • high density (to minimize tank weight),
  • low hazard factor (e.g., corrosivity and toxicity),
  • low environmental impact,
  • low cost.

Learn more about propellants here ;

brainly.com/question/1395855

#SPJ1

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If you complete and balance the following oxidation-reduction reaction in basic solution NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(a
andreev551 [17]

Answer:

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

Explanation:

NO2−(aq) + Al(s) → NH3(aq) + Al(OH)4−(aq)

Step 1: The half reactions

NO2- (aq) → NH3(g)

Al(s) → Al(OH)4-

<u>Step 2: </u>Balancing electrons

NO2- → NH3

On the left side N has an oxidation number of +3 and on the right side -3.

NO2- +6e-→ NH3

Al(s) → Al(OH)4-

On the left side, Al has an oxidation number of 0 and on the right side +3.

Al(s) → Al(OH)4- +3e-

To have the same amount of electrons transfered, we have to multiply the second reaction by 2

NO2- +6e-→ NH3

2(Al(s) → Al(OH)4- +6e-)

<u>Step 3:</u> Balance with OH/H2O

NO2- +6e +5H2O → NH3 +7OH-

2Al +8OH- → 2Al(OH)4- + 6e-

<u>Step 4:</u> The netto reaction

NO2- + 5H2O + 2Al + 8OH-  → NH3 +7OH- + 2Al(OH)4-

NO2- + 5H2O + 2Al + OH- → NH3 + 2Al(OH)4-

There is 1 hydroxide ion, on the reactant side

6 0
4 years ago
¿Cuántos moles hay en 101,64 g de (NH4)²SO⁴?
Alex_Xolod [135]

10164g HK momjkjioikpllp

3 0
3 years ago
Formula semidesarrollada de los hidrocarburos aromáticos de 1 a 10 átomos de carbono
Tju [1.3M]

Answer:

El principal componente del gas natural es también el hidrocarburo más simple: el metano. Este compuesto está formado por un átomo de carbono y cuatro átomos de hidrógeno y se representa de dos formas:

El hidrocarburo que le sigue en simplicidad es aquel que está constituido por dos átomos de carbono. Su fórmula condensada es C2H6 y se le conoce como etano.

Si se continúan colocando átomos de carbono con enlaces sencillos entre ellos e hidrógenos en los enlaces libres, se crean largas cadenas de compuestos. Al etano le sigue el propano (C2H8) y a éste, el butano (C4H10). Todos estos compuestos forman parte de la familia de los alcanos, y sus nombres terminan con el sufijo –ano para indicar que pertenecen a la misma familia.

3 0
3 years ago
What causes the surface ocean currents in the Northern Hemisphere to deflect to the right, and the currents in the Southern Hemi
AVprozaik [17]
The Coriolis force is an inertial force that acts on objects that are in motion relative to a rotation reference frame. This causes moving objects to the right ( with respect to the direction of travel ) in the Northern hemisphere and to the left in the Southern hemisphere. The horizontal deflection is zero at the equator. It also causes the surface ocean currents in the Northern hemisphere to deflect to the right and the currents in the Southern hemisphere to deflect to the left.
Answer: the Coriolis force.  
4 0
3 years ago
Carbon tetrachloride, CCl4, was once used as a dry cleaning solvent, but is no longer used because it is carcinogenic. At 57.8 °
Mila [183]
This problem is to use the Claussius-Clapeyron Equation, which is:

ln [p2 / p1] = ΔH/R [1/T2 - 1/T1]

Where p2 and p1 and vapor pressure at estates 2 and 1

ΔH is the enthalpy of vaporization

R is the universal constant of gases = 8.314 J / mol*K

T2 and T1 are the temperatures at the estates 2 and 1.

The  normal boiling point => 1 atm (the pressure of the atmosphere at sea level) = 101,325 kPa

Then p2 = 101.325 kPa
T2 = ?
p1 = 54.0 kPa
T1 = 57.8 °C + 273.15K = 330.95 K
ΔH = 33.05 kJ/mol = 33,050 J/mol 

=> ln [101.325/54.0] = [ (33,050 J/mol) / (8.314 J/mol*K) ] * [1/x - 1/330.95]

=> 0.629349 = 3975.22 [1/x - 1/330.95] = > 1/x =  0.000157 + 1/330.95 = 0.003179

=> x = 314.6 K => 314.6 - 273.15 = 41.5°C

Answer: 41.5 °C 
3 0
4 years ago
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