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mihalych1998 [28]
2 years ago
9

Hydrazine is a great chemical propellant because it creates a lot of gaseous products that need to expand and escape from their

reaction space. Based on this information, what physical characteristics of a reaction would you look for when trying to find new propellants?
Chemistry
1 answer:
Burka [1]2 years ago
4 0

We have to look for safe and non - hazardous characterstics when trying to find new propellants.

<h3>What are propellants ?</h3>

Propellants are any gas, liquid, or solid the expansion of which can be used to impart motion to another substance or object.

The Desirable properties for propellant combinations are ;

  • low molecular mass and high temperature of reaction products (for high exhaust velocity),
  • high density (to minimize tank weight),
  • low hazard factor (e.g., corrosivity and toxicity),
  • low environmental impact,
  • low cost.

Learn more about propellants here ;

brainly.com/question/1395855

#SPJ1

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POLAR BONDS will form.

A polar bond is a covalent bond between two atoms where the electrons forming the bond are unequally distributed. This causes the molecule to have a slight electrical dipole moment where one end is slightly positive and the other is slightly negative.

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Which thunderstorms hazard caused more than 450 deaths in Florida between 1959 and 2013
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Read 2 more answers
A 40.5 g sample of aluminum is cooled 7.5°C. The specific heat capacity of aluminum is
sweet-ann [11.9K]
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3 0
3 years ago
A. Which reactant is the limiting reagent?
Tasya [4]

Answer:

a. Zinc is the limiting reactant.

b. m_{ZnBr_2}^{by\ Zn}=162.61gZnBr_2

c. m_{Br_2}^{leftover}=6.6g

Explanation:

Hello there!

a. In this case, when zinc metal reacts with bromine, the following chemical reaction takes place:

Zn+Br_2\rightarrow ZnBr_2

Thus, since zinc and bromine react in a 1:1 mole ratio, we can compute their reacting moles to identify the limiting reactant:

n_{Zn}=47.2g*\frac{1mol}{65.38g} =0.722molZn\\\\n_{Br_2}=122g*\frac{1mol}{159.8g} =0.763molBr_2

Thus, since zinc has the fewest moles we infer it is the limiting reactant.

b. Here, we compute the grams of zinc bromide via both reactants:

m_{ZnBr_2}^{by\ Zn}=0.722molZn*\frac{1molZnBr_3}{1molZn} *\frac{225.22gZnBr_2}{1molZnBr_2} =162.61gZnBr_2\\\\m_{ZnBr_2}^{by\ Br_2}=0.763molBr_2*\frac{1molZnBr_3}{1molBr_2} *\frac{225.22gZnBr_2}{1molZnBr_2} =171.95gZnBr_2

That is why zinc is the limiting reactant, as it yields the fewest moles of zinc bromide product.

c. Here, since just 0.722 mol of bromine would react, we compute the corresponding mass:

m_{Br_2}^{reacted}=0.722molBr_2*\frac{159.8gBr_2}{1molBr_2} =115.4gBr_2

Thus, the leftover of bromine is:

m_{Br_2}^{leftover}=122g-115.4g\\\\m_{Br_2}^{leftover}=6.6g

Best regards!

8 0
3 years ago
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