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Lunna [17]
3 years ago
6

Dry air can be liquified at temperatures below 78.8K. This material is an

Chemistry
1 answer:
Vlad1618 [11]3 years ago
7 0
<h2>Answer : </h2>

<h3>D. HETEROGENEOUS MIXTURE </h3>

HOPE IT HELP ❤️

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Where should the neutrons be added to this atomic model?
Lera25 [3.4K]

Answer:

with the proton inside the nucleus

4 0
3 years ago
How many grams of oxygen are in 50.00 g of sucrose? Show your work
Marta_Voda [28]
Just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.
3 0
3 years ago
Read 2 more answers
Why do you think the same color M&amp;M was used in each sample of water?
Colt1911 [192]

Answer:

The candy coating is made up of coloring and sugar. The coloring and the sugar molecules both have positive and negative charges on them. The water molecule has positive and negative charges so it can attract and dissolve the color and sugar pretty well.

Explanation:

go to https://www.acs.org/content/acs/en/education/whatischemistry/adventures-in-chemistry/experiments/dissolving-m-ms.html#:~:text=The%20candy%20coating%20is%20made,color%20and%20sugar%20pretty%20well.

5 0
3 years ago
The average atomic mass of oxygen is 15.9994 amu. The atomic masses of its three isotopes are as follows: O-16: 15.995 amu; O-17
motikmotik
The average atomic mass of oxygen is the atomic mass with respect to 1/12th the mass of a C-12 atom, related to natural abundance. 
amu - atomic mass units 
O-16 - 15.995 amu
O-17 - 16.999 amu
O-18 - 17.999 amu
the average atomic mass is 15.9994 amu
average atomic mass = ∑atomic mass of each isotope * relative abundance percentage
in other words the average atomic mass is closer to the atomic mass of the most abundant isotope. In this case 15.9994 is closest to 15.995 amu which is the atomic mass of O-16.
This means that O-16 is the most abundant isotope.

7 0
4 years ago
A 0.100 m solution of butanoic acid has a % deprotonation of 1.23%. determine the ph of the butanoic acid solution.
MrRissso [65]
Chemical reaction: C₃H₇COOH → C₃H₇COO⁻ + H⁺.
c(<span>butanoic acid) = 0,100 M.
</span>α = 1,23% = 0,0123.
Ka = α² · c / 1 - α.
Ka = 0,0123² · 0,1 M / 1 - 0,0123.
Ka = 0,0000153 M.
Ka = c(C₃H₇COO⁻) · c(H⁺) / c(C₃H₇COOH).
c(H⁺) = α · c(C₃H₇COOH).
c(H⁺) = 0,0123 · 0,1 M = 0,00123 mol/L.
pH = -log c(H⁺).
pH = 2,91.

4 0
3 years ago
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