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Lunna [17]
3 years ago
6

Dry air can be liquified at temperatures below 78.8K. This material is an

Chemistry
1 answer:
Vlad1618 [11]3 years ago
7 0
<h2>Answer : </h2>

<h3>D. HETEROGENEOUS MIXTURE </h3>

HOPE IT HELP ❤️

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Why the compound containing calcium and chlorine is classified as an ionic compound.
Paraphin [41]
It contains metal, and non-metal. Metal gives electrons forming positive ion, non-metal takes electrons forming negative ion. So, between metal and non-metal ionic bond is formed
6 0
4 years ago
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An atom of 132sn has a mass of 131. 917760 amu. mass of1h atom = 1. 007825 amu mass of a neutron = 1. 008665 amu. calculate the
Lelechka [254]

The mass defect in amu/atom is 11.928.

The mass defect is the discrepancy between the nucleus of an atom's anticipated mass and its actual mass. This discrepancy is due to the binding energy of a system, which might manifest as excess mass.

The nucleus must be robustly spherical as expected for a doubly magical nucleus because the stripped neutron fell into a distinct orbital shell above the closed inner shells of tin-132 after the researchers examined the energy and angular distribution of the particles.

Mass of atom = 131.917760 amu

Mass of proton = 1.007825 amu

Mass of neutron = 1.008665 amu

Sn atom has 50 protons and 69 neutrons.

Mass defect = Mp + Mn - MA

                    = 50 × 1.007825 + 69 × 1.008665 - 131.917760

                    = 50.39125 + 69.597885 - 131.917760

                    = 11.928 amu/atom

Therefore, the mass defect in amu/atom is 11.928.

Learn more about mass defects here:

brainly.com/question/11410788

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6 0
2 years ago
Which options identify what the arrows in the diagram
Stolb23 [73]

Answer:

D

Explanation:

8 0
3 years ago
An appliance's energy use over time is called its _____ .
seropon [69]

The answer is power rating

4 0
3 years ago
Calculate the maximum amount of CO2 that can be produced when 64.0 g of O2 and 64.0 g of CH3OH are mixed for the reaction 2 CH3O
Triss [41]

Answer:

58.7g

Explanation:

From the reaction equation, we can see that 3 moles of oxygen yielded 2 moles of carbon (iv) oxide. Let's keep this for later.

Now, we calculate the actual number of moles of oxygen reacted. This can be calculated as follows.

The number of moles of oxygen reacted = mass of oxygen reacted ÷ molar mass of oxygen molecule.

The mass of oxygen reacted is 64g. Now, the molar mass of the oxygen molecule can be calculated from the atomic mass of the oxygen atom. The atomic mass of the oxygen atom is 16 a.m.u .Hence the molar mass = 2 × 16 = 32g/mol.

The number of moles is thus 64 ÷ 32 = 2 moles.

We now calculate the number of moles of Carbon iv oxide yielded.

As said from the beginning of the equation, 3 moles oxygen yielded 2 moles 2 moles CO2. Hence, moles oxygen will yield (2 ×2) ÷ 3 = 4/3 moles O2.

Now we calculate the mass of CO2 yielded.

The mass is = number of moles of CO2 yielded × molar mass of CO2.

Molar mass of CO2 = 12 + 2(16) = 44g/mol.

The mass is thus = 4/3 × 44 = 58.66667g

5 0
3 years ago
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