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Blizzard [7]
3 years ago
10

a 5.00 × 105 kg rocket is accelerating straight up. Its engines produce 1.50 × 107 of thrust, and air resistance is 4.50 × 106 N

. What is the rocket’s acceleration?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
3 0
This one is simple :)

use the equation F = ma and then re-arrange for a.

a = F / m

But there is a trick, so be careful. the question gives you wind resistance. Simply subtract the wind resistance from the thrust of the rocket to get the net force upward.

1.50 * 10^7N - 4.5 8 10^6N = 1.05 * 10^7N

So,

a =  \frac{F}{m} =  \frac{1.05*10^7N}{5.00*10^5kg}
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To find the answer, we need to know about the time of flight and range of projectile motion.

<h3>What's the expression of range of a projectile motion?</h3>
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<h3>What's the expression of time of flight in projectile motion?</h3>
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speed = distance /time

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