Answer:
-4.167m/s, 81.2385m
Explanation:
initial velocity=120km/hr = 33.33m/s
final velocity=75km/hr = 20.83 m/s
t=3s
Acceleration=v-u/t
a=(20.83-33.33)/3
a=-12.5/3
a=-4.167
Therefore, the acceleration is -4.167 m/s^2
s=ut+1/2at^2
33.33*3+1/2*-4.167*3^2
81.2385 m
Answer:
5.9 cm
Explanation:
We'll begin by calculating the spring constant (K) of the spring. This can be obtained as follow:
Force (F) = 15 N
Extention (e) = 3 cm
Spring constant (K) =.?
F = Ke
15 = K × 3
Divide both side by 3
K = 15 / 3
K = 5 N/cm
Therefore, the spring constant (K) is 5 N/cm.
Now, we shall determine how far the spring will stretch when a 3 kg candy is placed on the spring balance.
This can be obtained as follow:
First, we shall determine the weight of the object.
Mass of object = 3 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
W = mg
W = 3 × 9.8
W = 29.4 N
Finally, we shall determine how far the spring will stretch as follow:
Weight (W) = Force (F) = 29.4 N
Spring constant (K) = 5 N/cm
Extention (e) =?
F = ke
29.4 = 5 × e
Divide both side by 5
e = 29.4 / 5
e = 5.88 ≈ 5.9 cm
Therefore, the spring will stretch 5.9 cm when a 3 kg candy is placed on the spring balance.
Answer:
Ordinal
Explanation:
There are four levels of measurement which include the nominal, ordinal, interval, and ratio. The data collected above is ordinal data as it qualifies the data and still indicates the ordering of the data. It gives the observer an idea of the range of data collected or its rating although mathematical calculations may not be done with it.
The other forms of data include the nominal which simply qualifies the data, the interval which qualifies the data but which the differences between the data can be obtained, and of course the data has no starting point. The ratio scale which is similar to the interval scale but which the ratios between the data obtained can be compared.
It is velocity
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C. Volume and pressure
Key words: increases and decreases