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san4es73 [151]
3 years ago
9

A red car and a blue car can move along the same straight one-lane road. Both cars can move only at one speed when they move (e.

g., 60 mph). The driver of the red car sounds his horn. In which one of the following situations does the driver of the blue car hear the highest horn frequency?a. Both cars are moving at the same speed, and they are moving apart.b. Both cars are moving in the same direction at the same speed.c. Both cars are moving at the same speed, and they are moving toward each other.d. The red car is moving toward the blue car, which is stationary.e. The blue car is moving toward the red car, which is stationary.
Physics
1 answer:
baherus [9]3 years ago
4 0

Answer:c

Explanation:

When both cars move towards each other with same speed , apparent frequency will be highest

this can also be explained by Doppler frequency Formula

f'=f\left ( \frac{v+v_o}{v-v_s}\right )

where f'=Apparent\ frequency

f=Original\ frequency

v_o=velocity\ of\ observer

v_s=velocity\ of\ source

v=velocity\ of\ sound

as denominator is smaller than Numerator therefore apparent frequency will be greater

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A hollow conducting spherical shell has radii of 0.80 m and 1.20 m, The radial component of the electric field at a point that i
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Complete Question

The complete question is  shown on the first uploaded image  

 

Answer:

The electric field at that point is  E = 7500 \ N/C

Explanation:

From the question we are told that  

       The  radius of the inner circle is r_i  =  0.80  \ m

        The  radius of the outer circle is  r_o  =  1.20 \ m

       The  charge on the spherical shell q_n  =  -500nC  = -500*10^{-9} \ C

      The magnitude of the point charge at the center is  q_c =  + 300 nC  =  + 300 * 10^{-9} \ C

        The  position we are considering is  x =  0.60 m  from the center

Generally  the  electric field  at the distance x =  0.60 m  from the center  is mathematically represented as

                 E =  \frac{k *  q_c   }{x^2}

substituting values  

                  E =  \frac{k *  q_c   }{x^2}

where  k is  the coulomb constant with value k = 9*10^{9}  \ kg\cdot m^3\cdot s^{-4} \cdot A^{-2}.

     substituting values

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3 years ago
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Integrating the velocity equation, we will see that the position equation is:

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<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

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To get the position equation we just need to integrate the above equation:

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Replacing that in our integral we get:

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To learn more about motion equations, refer to:

brainly.com/question/19365526

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