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Alisiya [41]
3 years ago
11

Help please! Science!

Physics
2 answers:
muminat3 years ago
7 0

Answer:

My best guess is B. Sorry if I couldn't be of more help but that is the most likely answer.

My request: Please leave a follow, it would help a lot!

ira [324]3 years ago
4 0
It’s b!! thermal energy has very free molecules
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A car accelerates from 21.0 m/s to 46.0 m/s in 2.5 seconds. What is the acceleration of the car.
vivado [14]

Answer:

10.0 m/s^2

Explanation:

The acceleration of an object is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time interval it takes for the velocity to change from u to v

For the car in this problem,

u = 21.0 m/s

v = 46.0 m/s

t = 2.5 s

Substituting, we find the acceleration

a=\frac{46.0-21.0}{2.5}=10.0 m/s^2

6 0
3 years ago
How do they make pickle sunflower seeds?
Kobotan [32]

<em>Preheat oven to 350°F. Spray large baking sheet with cooking spray. </em>

<em> </em>

<em>Place dill, garlic powder, onion powder, salt, sugar and ascorbic acid in small bowl and stir to combine. </em>

<em> </em>

<em>Generously season sunflower seeds with dill mixture and toss to combine. Taste and season again, if needed. </em>

<em> </em>

<em>Arrange seeds on baking sheet and transfer to oven to brown for 10 to 15 minutes, tossing every 5 minutes to prevent burning. </em>

<em> </em>

<em>Remove from oven, let cool and store in airtight container.</em>

7 0
3 years ago
Read 2 more answers
X rays of wavelength 0.0100 nm are directed in the positive direction of an x axis onto a target containing loosely bound electr
Fofino [41]

Answer:

a)  =4.84*10^{-12}

b)= -2.76*10^{-14} J

c)i.e -2.76*10^{-14} J

d)= 0 and the direction of motion is equal to zero

Explanation:

a) compton shift

\Delta\lambda = \frac{h}{mc} (1-cos\theta)

\Delta\lambda = \frac{6.626*10^{-34}}{9.11*10^{-11}3*10^8} (1-cos180)

                        =4.84*10^{-12}

b) the new wavelength

\lambda' = 10.0*10^{-12} +4.84^10^{-12}

               =14.84*10^{-12} m

\Delta E = E' - E

              =hc[\frac{1}{\lambda'}-\frac{1}{\lambda}]

\Delta E = 6.626*10^{-34}*(3*10^8)[\frac{1}{14.84*10^{-12}}-\frac{1}{4.8*10^{-12}}]

= -2.76*10^{-14} J

C)By conservation of energy, the kinetic energy of recoiling electron is equal to the magnitude of energy between the photon energy

i.e -2.76*10^{-14} J

d) the angle between the positive direction of motion

sin\phy = \frac{\lambda_t sin\theta}{\lambda'}

            =\frac{2.43*10^{-12}sin180}{14.84*10^{-12}}  

             = 0

the direction of motion is equal to zero.

4 0
4 years ago
The block shown above has a mass of 105 g.<br> What is the density of the block? SC.8.P.8.3
zaharov [31]

The density of the block is 1.25 cm³

The correct answer to the question is Option B. 1.25 cm³

To solve this question, we'll begin by calculating the volume of the block. This can be obtained as follow:

Length = 7 cm

Height = 4 cm

Width = 3 cm

<h3>Volume =? </h3>

Volume = Length × Width × Height

Volume = 7 × 3 × 4

<h3>Volume = 84 cm³</h3>

Thus, the volume of the block is 84 cm³

Finally, we shall determine the density of the block. This can be obtained as follow:

Density is defined as mass per unit volume i.e

Density = \frac{mass}{volume} \\\\

Mass of block = 105 g

Volume of block = 84 cm³

<h3>Density of block =? </h3>

Density = \frac{mass}{volume}\\\\Density = \frac{105}{84}\\\\

<h3>Density of block = 1.25 cm³</h3>

Therefore, the density of the block is 1.25 cm³.

Hence, Option B. 1.25 cm³ gives the correct answer to the question.

Learn more: brainly.com/question/2040396?referrer=searchResults

4 0
2 years ago
A beam of light of wavelength lambda = 541nm is normally incident on a diffraction grating which has 600 lines m * m ^ - 1 Deter
MrMuchimi

Answer:

Angle of diffraction for second order maxima is θ = 18.941°

Explanation:

From the question it is given that

wavelength of incident light = λ = 541 nm = 541 x 10^-^9 m

order of maxima = n =2

diffraction grating has 600 lines per mm

⇒ distance between two slit is \frac{1mm}{600} = 1.66 x 10^-^6 m

using the relation of Braggs diffraction formula i.e.,

2dsinθ = nλ ..................................(1)

where, d = distance between two lines of grating

θ is the angle of diffraction

n= order of maxima

λ is the intensity of incident photon

on substituting the respected values in relation (1) we get,

2 x 1.66 x 10^-^6m sinθ = 2 x 541 x 10^-^9 m

⇒ sinθ = 0.3246

⇒ θ = sin^-^1(0.3246) = 18.941 °

8 0
3 years ago
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